Comparison of 2 string variables in shell script

Consider there is a variable line and variable word:

line = 1234 abc xyz 5678
word = 1234

The value of these variables are read from 2 different files.

I want to print the line if it contains the word. How do I do this using shell script? I tried all the suggested solutions given in previous questions. For example, the following code always passed even if the word was not in the line.

if [ "$line"==*"$word"*]; then
    echo $line
fi

---

No need for an if statement; just use grep :

echo $line | grep "b$wordb"

---

You can use if [[ "$line" == *"$word"* ]]

Also you need to use the following to assign variables

line="1234 abc xyz 5678"
word="1234"

Working example -- http://ideone.com/drLidd

---

Watch the white spaces!

When you set a variable to a value, don't put white spaces around the equal sign. Also use quotes when your value has spaced in it:

line="1234 abc xyz 5678"   # Must have quotation marks
word=1234                  # Quotation marks are optional

When you use comparisons, you must leave white space around the brackets and the comparison sign:

if [[ $line == *$word* ]]; then
    echo $line
fi

Note that double square brackets. If you are doing pattern matching, you must use the double square brackets and not the single square brackets. The double square brackets mean you're doing a pattern match operation when you use == or = . If you use single square brackets:

if [ "$line" = *"$word"* ]

You're doing equality. Note that double square brackets don't need quotation marks while single brackets it is required in most situations.

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