How to implement a property in an interface

I have interface IResourcePolicy containing the property Version . I have to implement this property which contain value, the code written in other pages:

IResourcePolicy irp(instantiated interface)
irp.WrmVersion = "10.4";

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How can I implement property version ?

public interface IResourcePolicy
{
   string Version
      {
          get;
          set;
      }
}

---

In the interface, you specify the property:

public interface IResourcePolicy
{
   string Version { get; set; }
}

In the implementing class, you need to implement it:

public class ResourcePolicy : IResourcePolicy
{
   public string Version { get; set; }
}

This looks similar, but it is something completely different. In the interface, there is no code. You just specify that there is a property with a getter and a setter, whatever they will do.

In the class, you actually implement them. The shortest way to do this is using this { get; set; } { get; set; } { get; set; } syntax. The compiler will create a field and generate the getter and setter implementation for it.

---

你的意思是这样吗？

class MyResourcePolicy : IResourcePolicy {
    private string version;

    public string Version {
        get {
            return this.version;
        }
        set {
            this.version = value;
        }
    }
}

---

Interfaces can not contain any implementation (including default values). You need to switch to abstract class.

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