Opening all files in a folder, and applying a function
I am doing a relatively simple piece of analysis which I have put into a function, on all the files in a particular folder. I was wondering whether anyone had any tips to help me automate the process on a number of different folders.
files <- (Sys.glob("*.csv"))
...which I found from Using R to list all files with a specified extension
And then the following code reads all those files into R.
listOfFiles <- lapply(files, function(x) read.table(x, header = FALSE))
…from Manipulating multiple files in R
But the files seem to be read in as one continuous list and not individual files… how can I change the script to open all the csv files in a particular folder as individual dataframes?
Secondly, assuming that I can read all the files in separately, how do I complete a function on all these dataframes in one go. For example, I have created four small dataframes so I can illustrate what I want:
Df.1 <- data.frame(A = c(5,4,7,6,8,4),B = (c(1,5,2,4,9,1)))
Df.2 <- data.frame(A = c(1:6),B = (c(2,3,4,5,1,1)))
Df.3 <- data.frame(A = c(4,6,8,0,1,11),B = (c(7,6,5,9,1,15)))
Df.4 <- data.frame(A = c(4,2,6,8,1,0),B = (c(3,1,9,11,2,16)))
I have also made up an example function:
Summary<-function(dfile){
SumA<-sum(dfile$A)
MinA<-min(dfile$A)
MeanA<-mean(dfile$A)
MedianA<-median(dfile$A)
MaxA<-max(dfile$A)
sumB<-sum(dfile$B)
MinB<-min(dfile$B)
MeanB<-mean(dfile$B)
MedianB<-median(dfile$B)
MaxB<-max(dfile$B)
Sum<-c(sumA,sumB)
Min<-c(MinA,MinB)
Mean<-c(MeanA,MeanB)
Median<-c(MedianA,MedianB)
Max<-c(MaxA,MaxB)
rm(sumA,sumB,MinA,MinB,MeanA,MeanB,MedianA,MedianB,MaxA,MaxB)
Label<-c("A","B")
dfile_summary<-data.frame(Label,Sum,Min,Mean,Median,Max)
return(dfile_summary)}
I would ordinarily use the following command to apply the function to each individual dataframe.
Df1.summary<-Summary(dfile)
Is there a way instead of applying the function to all the dataframes, and use the titles of the dataframes in the summary tables (ie Df1.summary).
Many thanks,
Katie
On the contrary, I do think working with list
makes it easy to automate such things.
Here is one solution (I stored your four dataframes in folder temp/
).
filenames <- list.files("temp", pattern="*.csv", full.names=TRUE)
ldf <- lapply(filenames, read.csv)
res <- lapply(ldf, summary)
names(res) <- substr(filenames, 6, 30)
It is important to store the full path for your files (as I did with full.names
), otherwise you have to paste the working directory, eg
filenames <- list.files("temp", pattern="*.csv")
paste("temp", filenames, sep="/")
will work too. Note that I used substr
to extract file names while discarding full path.
You can access your summary tables as follows:
> res$`df4.csv`
A B
Min. :0.00 Min. : 1.00
1st Qu.:1.25 1st Qu.: 2.25
Median :3.00 Median : 6.00
Mean :3.50 Mean : 7.00
3rd Qu.:5.50 3rd Qu.:10.50
Max. :8.00 Max. :16.00
If you really want to get individual summary tables, you can extract them afterwards. Eg,
for (i in 1:length(res))
assign(paste(paste("df", i, sep=""), "summary", sep="."), res[[i]])
usually i don't use for loop in R, but here is my solution using for loops and two packages : plyr and dostats
plyr is on cran and you can download dostats on https://github.com/halpo/dostats (may be using install_github from Hadley devtools package)
Assuming that i have your first two data.frame (Df.1 and Df.2) in csv files, you can do something like this.
require(plyr)
require(dostats)
files <- list.files(pattern = ".csv")
for (i in seq_along(files)) {
assign(paste("Df", i, sep = "."), read.csv(files[i]))
assign(paste(paste("Df", i, sep = ""), "summary", sep = "."),
ldply(get(paste("Df", i, sep = ".")), dostats, sum, min, mean, median, max))
}
Here is the output
R> Df1.summary
.id sum min mean median max
1 A 34 4 5.6667 5.5 8
2 B 22 1 3.6667 3.0 9
R> Df2.summary
.id sum min mean median max
1 A 21 1 3.5000 3.5 6
2 B 16 1 2.6667 2.5 5
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