如何合并具有相同键名的两个字典

这个问题在这里已经有了答案:

  • Python中的append和extend列表方法之间的区别22回答

  • 如果您想要一个不会改变原始字典并查看名称冲突的合并副本,则可能需要尝试此解决方案:

    >>> dict1 = {'a': [1], 'b': [2]}
    >>> dict2 = {'b': [3], 'c': [4]}
    >>> import copy
    >>> import itertools
    >>> def merge(a, b, conflict):
        new = copy.deepcopy(a)
        if conflict:
            for key, value in b.items():
                if key in new:
                    counter = itertools.count(1)
                    # Rename 1st key.
                    while True:
                        name = '{}_{}'.format(key, next(counter))
                        if name not in new:
                            new[name] = new[key]
                            del new[key]
                            break
                    # Create 2nd key.
                    while True:
                        name = '{}_{}'.format(key, next(counter))
                        if name not in new:
                            new[name] = value
                            break
                else:
                    new[key] = value
        else:
            for key, value in b.items():
                new.setdefault(key, []).extend(value)
        return new
    
    >>> merge(dict1, dict2, False)
    {'c': [4], 'b': [2, 3], 'a': [1]}
    >>> merge(dict1, dict2, True)
    {'b_2': [3], 'b_1': [2], 'c': [4], 'a': [1]}
    

    我想你想要这个:

    dict1 = {'a':[1], 'b':[2]}
    dict2 = {'b':[3], 'c':[4]}
    
    def mergeArray(conflict):
        for key in dict1.keys():
            if dict2.has_key(key):
                if conflict==False:
                    dict2[key].extend(dict1[key])
                else:
                    dict2[key+'_1'] = dict1[key]
                    dict2[key+'_2'] = dict2.pop(key)
            else:
                dict2[key] = dict1[key]
    
    mergeArray(True);
    print dict2
    
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