`String.raw` when last character is `\`
String.raw is very useful. For example:
let path = String.raw`C:pathtofile.html`
However, when the last character of the template string is , it becomes an syntax error.
let path = String.raw`C:pathtodirectory`
Uncaught SyntaxError: Unterminated template literal
Tentatively, I use this method.
let path = String.raw`C:pathtodirectory `.trimRight()
Can I write template string which last character is using String.raw ?
Here are a few different possible workarounds. My favorite is probably creating a custom template tag dir to solve the problem for you. I think it makes the syntax cleaner and more semantic.
let path
// Uglier workarounds
path = String.raw `C:pathtodirectory${``}`
path = String.raw `C:pathtodirectory`+``
path = `C:pathtodirectory`
// Cleanest solution
const dir = ({raw}) => raw + ``
path = dir `C:pathtodirectory`
console.log(path)According to https://hacks.mozilla.org/2015/05/es6-in-depth-template-strings-2/ escape sequences are left untouched, aside from $ { and `, in template strings. Thus one cannot escape the escape character. Based on this it looks like your solution is the best way to achieve your goal.
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