通过POST（ajax）发送JSON数据并接收来自Controller（MVC）的json响应

我在JavaScript中创建了一个函数：

function addNewManufacturer() {
       var name = $("#id-manuf-name").val();
       var address = $("#id-manuf-address").val();
       var phone = $("#id-manuf-phone").val();

       var sendInfo = {
           Name: name,
           Address: address,
           Phone: phone
       };

       $.ajax({
           type: "POST",
           url: "/Home/Add",
           dataType: "json",
           success: function (msg) {
               if (msg) {
                   alert("Somebody" + name + " was added in list !");
                   location.reload(true);
               } else {
                   alert("Cannot add to list !");
               }
           },

           data: sendInfo
       });
}

我调用了jquery.json-2.3.min.js脚本文件，并将其用于toJSON(array)方法。

在控制器中，我有这个Add动作

[HttpPost]
public ActionResult Add(PersonSheets sendInfo) {
    bool success = _addSomethingInList.AddNewSomething( sendInfo );

    return this.Json( new {
         msg = success
    });

}

但sendInfo作为方法参数变为null。

该模型：

public struct PersonSheets
{
    public int Id;
    public string Name;
    public string Address;
    public string Phone;
}

public class PersonModel
{
    private List<PersonSheets> _list;
    public PersonModel() {
         _list= GetFakeData();
    }

    public bool AddNewSomething(PersonSheets info) {
         if ( (info as object) == null ) {
            throw new ArgumentException( "Person list cannot be empty", "info" );
         }

         PersonSheets item= new PersonSheets();
         item.Id = GetMaximumIdValueFromList( _list) + 1;
         item.Name = info.Name;
         item.Address = info.Address;
         item.Phone = info.Phone;

         _list.Add(item);

         return true;
    }
}

如何在数据与POST一起发送时以行动方式执行操作？

我不知道如何使用。 此外，有可能通过JSON发送回应（到ajax）？

谢谢

---

创建一个模型

public class Person
{
    public string Name { get; set; }
    public string Address { get; set; }
    public string Phone { get; set; }
}

像下面的控制器

    public ActionResult PersonTest()
    {
        return View();
    }

    [HttpPost]
    public ActionResult PersonSubmit(Vh.Web.Models.Person person)
    {
        System.Threading.Thread.Sleep(2000);  /*simulating slow connection*/

        /*Do something with object person*/


        return Json(new {msg="Successfully added "+person.Name });
    }

使用Javascript

<script type="text/javascript">
    function send() {
        var person = {
            name: $("#id-name").val(),
            address:$("#id-address").val(),
            phone:$("#id-phone").val()
        }

        $('#target').html('sending..');

        $.ajax({
            url: '/test/PersonSubmit',
            type: 'post',
            dataType: 'json',
            success: function (data) {
                $('#target').html(data.msg);
            },
            data: person
        });
    }
</script>

---

var SendInfo= { SendInfo: [... your elements ...]};

        $.ajax({
            type: 'post',
            url: 'Your-URI',
            data: JSON.stringify(SendInfo),
            contentType: "application/json; charset=utf-8",
            traditional: true,
            success: function (data) {
                ...
            }
        });

并在行动中

public ActionResult AddDomain(IEnumerable<PersonSheets> SendInfo){
...

你可以像这样绑定你的数组

var SendInfo = [];

$(this).parents('table').find('input:checked').each(function () {
    var domain = {
        name: $("#id-manuf-name").val(),
        address: $("#id-manuf-address").val(),
        phone: $("#id-manuf-phone").val(),
    }

    SendInfo.push(domain);
});

希望这可以帮到你。

---

使用JSON.stringify(<data>) 。

将您的代码： data: sendInfo更改为data: JSON.stringify(sendInfo) 。 希望这可以帮到你。

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