Rewriting Python switch into a more compact way
Possible Duplicate:
Replacements for switch statement in python?
Suppose I have a list in Python:
list = ('ADD', 'SUB', 'PUSH', 'POP')
I want to run a function depending on input, and that input can be any value in the list.
Instead of writing a switch case statement for each element in list , is there a more compact way of writing it?
My reasoning is for the case of the list growing in the future.
Well, there is no switch/case statement in Python.
For a small list , you want to use if / elif :
def do_stuff(x, *args):
if x == 'ADD':
return do_add(*args)
elif x == 'SUB':
return do_sub(*args)
# …
else:
raise RuntimeError('Never heard of {}'.format(x))
For a larger list , you want to make sure each case is a function (I already assumed that above, but if you had code like return args[0] + args[1] , you'd have to change that into a do_add function), and create a dict mapping names to functions:
func_map = {'ADD': do_add, 'SUB': do_sub, … }
def do_stuff(x, *args):
try:
return func_map[x](*args)
except KeyError:
raise RuntimeError('Never heard of {}'.format(x))
This works because in Python, functions are normal objects that you can pass around like any other objects. So, you can store them in a dict , retrieve them from the dict , and still call them.
By the way, this is all explained in the FAQ, along with a bit of extra fanciness.
If you have some default function you'd like to call instead of raising an error, it's obvious how to do that with the if / elif / else chain, but how do you do it with the dict map? You could do it by putting the default function into the except block, but there's an easier way: just use the dict.get method:
def do_stuff(x, *args):
return func_map.get(x, do_default)(*args)
你也可以使用这样的模式(匆忙所以不能清理atm):
>>> class Test(object):
... def test_FOO(self):
... print 'foo'
...
... def test_BAR(self):
... print 'bar'
...
>>> def run_on(cls, name):
... getattr(cls, 'test_%s' % name)()
...
>>> run_on(Test(), 'FOO')
foo
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