understanding the output of gprof on solaris
I thought of learning gprof.so i started with a simple program. I have written a small program in c below:
#include<stdio.h>
#include<unistd.h>
void hello(void);
int main()
{
hello();
return 0;
}
void hello()
{
int i;
for(i=0; i<60; i++)
{
sleep(1);
printf("hello worldn");
}
}
i compiled my program using -pg option. and i executed it to make sure that its working fine.
then i did
gprof -f hello a.out > gout
this gives me gout file created. inside the gout file i can see the below information.
% cumulative self self total
time seconds seconds calls ms/call ms/call name
-nan 0.00 0.00 3 0.00 0.00 __1cH__CimplWnew_atexit_implemented6F_b_ (1561)
-nan 0.00 0.00 1 0.00 0.00 __1cFhello6F_v_ (1562)
-nan 0.00 0.00 1 0.00 0.00 __1cG__CrunMdo_exit_code6F_v_ (1563)
-nan 0.00 0.00 1 0.00 0.00 __1cG__CrunSregister_exit_code6FpG_v_v_ (1564)
-nan 0.00 0.00 1 0.00 0.00 __1cG__CrunVdo_exit_code_in_range6Fpv1_v_ (1565)
-nan 0.00 0.00 1 0.00 0.00 __1cH__CimplKcplus_fini6F_v_ (1566)
-nan 0.00 0.00 1 0.00 0.00 __1cH__CimplQ__type_info_hash2t5B6M_v_ (1567)
-nan 0.00 0.00 1 0.00 0.00 __1cU__STATIC_CONSTRUCTOR6F_v_ (1568)
-nan 0.00 0.00 1 0.00 0.00 __SLIP.FINAL__A (1569)
-nan 0.00 0.00 1 0.00 0.00 __SLIP.INIT_A (1570)
-nan 0.00 0.00 1 0.00 0.00 __cplus_fini_at_exit (1571)
-nan 0.00 0.00 1 0.00 0.00 _ex_deregister (1572)
-nan 0.00 0.00 1 0.00 0.00 main (1)
^L
Index by function name
(1562) __1cFhello6F_v_ (1567) __1cH__CimplQ__type(1571) __cplus_fini_at_exi
(1563) __1cG__CrunMdo_exit(1561) __1cH__CimplWnew_at(1572) _ex_deregister
(1564) __1cG__CrunSregiste(1568) __1cU__STATIC_CONST (1) main
(1565) __1cG__CrunVdo_exit(1569) __SLIP.FINAL__A
(1566) __1cH__CimplKcplus_(1570) __SLIP.INIT_A
i have given a sleep time of 60 sec. and i am not seeing that 60 sec in the gprof output. i believe its probably hidden inside the output. could anybody pls help me understand the output of gprof?
gprof的示例不考虑I / O,睡眠和其他异步或阻止的OS系统调用,因此您无法在gprof报告中看到相关时间成本。
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