Extended slice that goes to beginning of sequence with negative stride
Bear with me while I explain my question. Skip down to the bold heading if you already understand extended slice list indexing.
In python, you can index lists using slice notation. Here's an example:
>>> A = list(range(10))
>>> A[0:5]
[0, 1, 2, 3, 4]
You can also include a stride, which acts like a "step":
>>> A[0:5:2]
[0, 2, 4]
The stride is also allowed to be negative, meaning the elements are retrieved in reverse order:
>>> A[5:0:-1]
[5, 4, 3, 2, 1]
But wait! I wanted to see [4, 3, 2, 1, 0]
. Oh, I see, I need to decrement the start and end indices:
>>> A[4:-1:-1]
[]
What happened? It's interpreting -1 as being at the end of the array, not the beginning. I know you can achieve this as follows:
>>> A[4::-1]
[4, 3, 2, 1, 0]
But you can't use this in all cases. For example, in a method that's been passed indices.
My question is:
Is there any good pythonic way of using extended slices with negative strides and explicit start and end indices that include the first element of a sequence?
This is what I've come up with so far, but it seems unsatisfying.
>>> A[0:5][::-1]
[4, 3, 2, 1, 0]
It is error-prone to change the semantics of start
and stop
. Use None
or -(len(a) + 1)
instead of 0
or -1
. The semantics is not arbitrary. See Edsger W. Dijkstra's article "Why numbering should start at zero".
>>> a = range(10)
>>> start, stop, step = 4, None, -1
Or
>>> start, stop, step = 4, -(len(a) + 1), -1
>>> a[start:stop:step]
[4, 3, 2, 1, 0]
Or
>>> s = slice(start, stop, step)
>>> a[s]
[4, 3, 2, 1, 0]
When s
is a sequence the negative indexes in s[i:j:k]
are treated specially:
If i
or j
is negative, the index is relative to the end of the string: len(s) + i
or len(s) + j
is substituted. But note that -0
is still 0
.
that is why len(range(10)[4:-1:-1]) == 0
because it is equivalent to range(10)[4:9:-1]
.
Ok, I think this is probably as good as I will get it. Thanks to Abgan for sparking the idea. This relies on the fact that None in a slice is treated as if it were a missing parameter. Anyone got anything better?
def getReversedList(aList, end, start, step):
return aList[end:start if start!=-1 else None:step]
edit: check for start==-1
, not 0
This is still not ideal, because you're clobbering the usual behavior of -1. It seems the problem here is two overlapping definitions of what's supposed to happen. Whoever wins takes away otherwise valid invocations looking for the other intention.
[ A[b] for b in range(end,start,stride) ]
Slower, however you can use negative indices, so this should work:
[ A[b] for b in range(9, -1, -1) ]
I realize this isn't using slices, but thought I'd offer the solution anyway if using slices specifically for getting the result isn't a priority.
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