Php form ajax "success & fail" message

The form on my website is a simple contact form. I would like the form to show a "success & failed" message on the same page when the form is sent/failed without reloading the page. I understand that I should use Ajax to do this but I can't get it to work because my knowledge about it is very little.

Here is the code I'm working with.

Html (single page design):

    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.js"></script>

<form class="form" id="contactus" action="" method="post" accept-charset="UTF-8">




                        <label for="nametag">Namn<FONT COLOR="#FF0060">*</FONT></label>

                        <input name="name" type="text" id="name"  value="" />




                        <label for="emailtag">Email<FONT COLOR="#FF0060">*</FONT></label>

                        <input name="email" type="text" id="email"  value="" />


                        <label for="phonetag">Telefon</label>

                        <input name="phone" type="text" id="phone"  value="" />


                        <label for="messagetag">Meddelande<FONT COLOR="#FF0060">*</FONT></label></br>

                        <textarea name="message" id="message" style="width: 87%; height: 200px;"></textarea>






<label class="placeholder">&nbsp;</label>

                        <button class="submit" name="submit">Skicka</button>



                </form> 



<script>        
    $(function() {
            $('#contactus').submit(function (event) {
                event.preventDefault();
                event.returnValue = false;
                $.ajax({
                    type: 'POST',
                    url: 'php/mail.php',
                    data: $('#contactus').serialize(),
                    success: function(res) {alert(res);
                        if (res == 'successful') {
                            $('#status').html('Sent').slideDown();
                        }
                        else {
                            $('#status').html('Failed').slideDown();
                        } 
                    },
                    error: function () {
                        $('#status').html('Failed').slideDown();
                    }
                });
            });
        });
    </script>   

Php:

<?php
    $name = $_POST['name'];
    $email = $_POST['email'];
    $phone = $_POST['phone'];
    $message = $_POST['message'];
    $recipient = "info@mydomain.com";
    $subject = "Webbkontakt";
    $formcontent = "Från: $name <br/> Email: $email <br/> Telefon: $phone <br/> Meddelande: $message";

    $headers = "From: " ."CAMAXON<info@mydomain.com>" . "rn";
    $headers .= "Reply-To: ". "no-reply@mydomain.com" . "rn";
    $headers .= "MIME-Version: 1.0rn";
    $headers .= "Content-Type: text/html; charset=utf-8rn";

    if(mail($recipient, $subject, $formcontent, $headers))
    {
        echo "successful";
    }
    else
    {
        echo "error";
    }
?>

---

Your Ajax call is not working properly. Try this

$(function() {
            $('#contactus').submit(function (event) {
                event.preventDefault();
                event.returnValue = false;
                $.ajax({
                    type: 'POST',
                    url: 'php/mail.php',
                    data: $('#contactus').serialize(),
                    success: function(res) {
                        if (res == 'successful') {
                            $('#status').html('Sent').slideDown();
                        }
                        else {
                            $('#status').html('Failed').slideDown();
                        } 
                    },
                    error: function () {
                        $('#status').html('Failed').slideDown();
                    }
                });
            });
        });

Also as you can see i have used $('#contactus').serialize() this way you dont need to pass the form elements one by one instead serialize() will pass the whole form elements to your php page

Than in your php file echo successful if everything went well else echo error if the response is an error than show the error div

<?php
    $name = $_POST['name'];
    $email = $_POST['email'];
    $phone = $_POST['phone'];
    $message = $_POST['message'];
    $recipient = "info@mydomain.com";
    $subject = "Webbkontakt";
    $formcontent = "Från: $name <br/> Email: $email <br/> Telefon: $phone <br/> Meddelande: $message";

    $headers = "From: " ."CAMAXON<info@mydomain.com>" . "rn";
    $headers .= "Reply-To: ". "no-reply@mydomain.com" . "rn";
    $headers .= "MIME-Version: 1.0rn";
    $headers .= "Content-Type: text/html; charset=ISO-8859-1rn";

    if(mail($recipient, $subject, $formcontent, $headers))
    {
        echo "successful";
    }
    else
    {
        echo "error";
    }
?>

---

像这样改变你的PHP脚本：

<?php
if( isset( $_POST['submit'] )){ //checking if form was submitted
$name = $_POST['name'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$message = $_POST['message'];
$formcontent="Meddelande: nn $message";
$recipient = "info@mydomain.com";
$subject = "Webbkontakt";
$mailheader = "Från: $name n Email: $email n Telefon: $phone rn";

$mailsent = mail($recipient, $subject, $formcontent, $mailheader);

if($mailsent) echo "Success"; //success if mail was sent
else echo "Ett fel uppstod!";
}
?>

---

在你的PHP脚本中，你可以试试这个

if(mail($recipient, $subject, $formcontent, $mailheaders))
{
  echo("Mail Sent Successfully"); // or echo(successful) in your case
}else{
  echo("Mail Not Sent"); // or die("Ett fel uppstod!");

}

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