如何简化参数的传递
我有这些方法在C＃中需要3个参数
public void Delete_AgentTools(int ID,int UAM,int mode)
{
some code etc.
}
我使用javascript ajax来调用这个方法并传递参数
function Delete_AgentTools(toolAccess, toolId, UAM) {
$.ajax({
type: "POST",
url: "IROA_StoredProcedures.asmx/Delete_AgentTools",
data: "{'toolAccess':'" + toolAccess + "', 'toolId':'" + toolId + "', 'UAM':'" + UAM + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success:function()
{
alert("Tool has been successfully delete");
},
error: function (XMLHttpRequest)
{
alert("error in Delete_AgentTools()");
console.log(XMLHttpRequest);
}
});
}
你看到我想简化我如何在JavaScript中传递参数。 是否有可能将它作为一个object传递给c#或简化在javascript传递parameters
您可以使用JSON.stringify将js对象转换为JSON
var data = {};
data.toolAccess = value1;
data.toolId = value2;
data.UAM = value3;
$.ajax({
type: "POST",
url: "IROA_StoredProcedures.asmx/Delete_AgentTools",
data: JSON.stringify(data),
contentType: "application/json; charset=utf-8",
dataType: "json",
success:function()
{
alert("Tool has been successfully delete");
},
error: function (XMLHttpRequest)
{
alert("error in Delete_AgentTools()");
console.log(XMLHttpRequest);
}
});
function Delete_AgentTools(toolAccess, toolId, UAM) {
var data = {};
data.mode = toolAccess;
data.ID = toolId;
data.UAM = UAM;
$.ajax({
type: "POST",
url: "IROA_StoredProcedures.asmx/Delete_AgentTools",
data: JSON.stringify(data),
contentType: "application/json; charset=utf-8",
dataType: "json",
success:function()
{
alert("Tool has been successfully delete");
},
error: function (XMLHttpRequest)
{
alert("error in Delete_AgentTools()");
console.log(XMLHttpRequest);
}
});
无需在您的C＃代码中进行更改。
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