How to convert firebase timestamp into date and time
I have tried to get date and time from firebase timestamp as follows:
Date date=new Date(timestamp*1000);
SimpleDateFormat sfd = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sfd.format(date)
but I'm getting results like:
:02-02-48450 04:21:54
:06-02-48450 10:09:45
:07-02-48450 00:48:35
as you can see the year is not as we live.
So, please help me to fix this.
Your timestamp 1466769937914 equals to 2016-06-24 12:05:37 UTC . The problem is that you are multiplying the timestamp by 1000 for no real reason, which in result gives you 1466769937914000 . And that equals to 48450-02-01 21:51:54 UTC , so results you are getting are technically correct and all is working fine. You just feed your code with wrong input data and this us the only part that must be fixed. A solution is simply to remove multiplication and you should be all good:
SimpleDateFormat sfd = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sfd.format(new Date(timestamp))
According to Firebase documentation, the types that are available JSON are:
String Long Double Boolean Map<String, Object> List<Object> Quoting another Stack Overflow post, I suggest you use JSON date string format yyyy-MM-dd'T'HH:mm:ss.SSSZ instead of epoch timestamp.
Comparing 1335205543511 to 2012-04-23T18:25:43.511Z , you can noticed that:
ISO 8601 has been well-established internationally for more than a decade and is endorsed by W3C, RFC3339, and XKCD
String time=dataSnapshot.child("timeStamp").getValue().toString(); Long t=Long.parseLong(time);
Date myDate = new Date(t*1000);
Result
Fri May 11 05:37:58 GMT+06:30
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