Bash脚本卷曲

#!/bin/bash

read -p 'Username: ' uservar
read -p 'Password: ' passvar

cacheVariable1=""Content-Type:application/json""
cacheVariable2=""Cache-Control:no-cache""
parametersVariable="'{"username":"$uservar","password":"$passvar"}'"
echo $parametersVariable
echo $cacheVariable1 $cacheVariable2
websiteVariable="https://example.com/session"

echo $websiteVariable

entireURL="curl -X POST -H "$cacheVariable1" -H "$cacheVariable2" -d "$parametersVariable" "$websiteVariable""

echo "Entire URL IS: $entireURL"

result=`$entireURL`


echo "$result"

我想我的脚本是这样的：curl -X POST -H“Content-Type：application / json”-H“Cache-Control：no-cache”-d'{“username”：“abc@abc.com”，“密码“：”Password123“}'”https://example.com/session“

整个URL是：curl -H“Content-Type：application / json”-H“Cache-Control：no-cache”-d'{“username”：“zzzzzz”，“password”：“azzzsass”}'https： //cloud.tenable.com/session

但它不在bash中执行。 它给了我这个错误：

{"statusCode":400,"error":"Bad Request","message":"child "username" fails because ["username" is required]","validation":{"source":"payload","keys":["username"]}}

但它不起作用。 谁能帮我？

更新

---

我自己解决了它。 一切都是正确的，除了执行作为eval $ entireURL。 由于嵌入在圆括号内的命令作为子外壳运行，因此我的环境变量缺失。

---

#!/bin/bash

read -p 'Username: ' uservar
read -p 'Password: ' passvar

cacheVariable1=""Content-Type:application/json""
cacheVariable2=""Cache-Control:no-cache""
parametersVariable="'{"username":"$uservar","password":"$passvar"}'"
echo $parametersVariable
echo $cacheVariable1 $cacheVariable2
websiteVariable="https://example.com/session"

echo $websiteVariable

entireURL="curl -X POST -H "$cacheVariable1" -H "$cacheVariable2" -d "$parametersVariable" "$websiteVariable""

echo "Entire URL IS: $entireURL"

result=`$entireURL`

eval $entireURL

这工作完美！

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