Do you cast the result of malloc?

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Why does C++ require a cast for malloc() but C doesn't? 3 answers

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In C, you can implicitly convert from a void* (the return type of malloc ) to any other pointer type. Therefore, the cast isn't required, and it's considered good C style to leave the cast off.

In C++, you cannot implicitly convert from a void* to any other pointer type, so the cast would be required. That said, in C++, you should almost certainly be using new and delete rather than malloc , as they're more type-safe, play well with constructors and destructors, etc.

Hope this helps!

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