How to get the type of T from a member of a generic class or method?
Let say I have a generic member in a class or method, so:
public class Foo<T>
{
public List<T> Bar { get; set; }
public void Baz()
{
// get type of T
}
}
When I instantiate the class, the T
becomes MyTypeObject1
, so the class has a generic list property: List<MyTypeObject1>
. The same applies to a generic method in a non-generic class:
public class Foo
{
public void Bar<T>()
{
var baz = new List<T>();
// get type of T
}
}
I would like to know, what type of objects the list of my class contains. So the list property called Bar
or the local variable baz
, contains what type of T
?
I cannot do Bar[0].GetType()
, because the list might contain zero elements. How can I do it?
If I understand correctly, your list has the same type parameter as the container class itself. If this is the case, then:
Type typeParameterType = typeof(T);
If you are in the lucky situation of having object
as a type parameter, see Marc's answer.
(note: I'm assuming that all you know is object
or IList
or similar, and that the list could be any type at runtime)
If you know it is a List<T>
, then:
Type type = abc.GetType().GetGenericArguments()[0];
Another option is to look at the indexer:
Type type = abc.GetType().GetProperty("Item").PropertyType;
Using new TypeInfo:
using System.Reflection;
// ...
var type = abc.GetType().GetTypeInfo().GenericTypeArguments[0];
With the following extension method you can get away without reflection:
public static Type GetListType<T>(this List<T> _)
{
return typeof(T);
}
Or more general:
public static Type GetEnumeratedType<T>(this IEnumerable<T> _)
{
return typeof(T);
}
Usage:
List<string> list = new List<string> { "a", "b", "c" };
IEnumerable<string> strings = list;
IEnumerable<object> objects = list;
Type listType = list.GetListType(); // string
Type stringsType = strings.GetEnumeratedType(); // string
Type objectsType = objects.GetEnumeratedType(); // BEWARE: object
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