UITableView Cell selected Color?

I have created a custom UITableViewCell . The table view is showing data fine. What I am stuck in is when user touches cell of tableview, then I want to show the background color of the cell other than the default [blue color] values for highlighting the selection of cell. I use this code but nothing happens:

cell.selectedBackgroundView.backgroundColor=[UIColor blackColor];

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I think you were on the right track, but according to the class definition for selectedBackgroundView :

The default is nil for cells in plain-style tables (UITableViewStylePlain) and non-nil for section-group tables UITableViewStyleGrouped).

Therefore, if you're using a plain-style table, then you'll need to alloc-init a new UIView having your desired background colour and then assign it to selectedBackgroundView .

Alternatively, you could use:

cell.selectionStyle = UITableViewCellSelectionStyleGray;

if all you wanted was a gray background when the cell is selected. Hope this helps.

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No need for custom cells. If you only want to change the selected color of the cell, you can do this:

Objective-C:

UIView *bgColorView = [[UIView alloc] init];
bgColorView.backgroundColor = [UIColor redColor];
[cell setSelectedBackgroundView:bgColorView];

Swift:

let bgColorView = UIView()
bgColorView.backgroundColor = UIColor.redColor()
cell.selectedBackgroundView = bgColorView

Swift 3:

let bgColorView = UIView()
bgColorView.backgroundColor = UIColor.red
cell.selectedBackgroundView = bgColorView

Edit: Updated for ARC

Edit: Adds Swift 3

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If you have a grouped table with just one cell per section, just add this extra line to the code: bgColorView.layer.cornerRadius = 10;

UIView *bgColorView = [[UIView alloc] init];
[bgColorView setBackgroundColor:[UIColor redColor]];
bgColorView.layer.cornerRadius = 10;
[cell setSelectedBackgroundView:bgColorView];
[bgColorView release]; 

Don't forget to import QuartzCore.

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