Multiple :g and :v commands in one statement

I have this file

foo
foo bar
foo bar baz
bar baz
foo baz
baz bar
bar
baz
foo 42
foo bar 42 baz
baz 42

I want to

Select lines which contain foo and do NOT contain bar

Delete lines which contain foo and do NOT contain bar

I read somewhere (can't find the link) that I have to use :exec with | for this.

I tried the following, but it doesn't work

:exec "g/foo" # works
:exec "g/foo" | exec "g/bar" -- first returns lines with foo, then with bar
:exec "g/foo" | :g/bar -- same as above

And ofcourse if I cannot select a line, I cannot execute normal dd on it.

Any ideas?

Edit

Note for the bounty:

I'm looking for a solution that uses proper :g and :v commands, and does not use regex hacks, as the conditions may not be the same (I can have 2 includes, 3 excludes).

Also note that the last 2 examples of things that don't work, they do work for just deleting the lines, but they return incorrect information when I run them without deleting (ie, viewing the selected lines) and they behave as mentioned above.

---

This might still be hackish to you, but you can write some vimscript to make a function and specialized command for this. For example:

command! -nargs=* -range=% G <line1>,<line2>call MultiG(<f-args>)
fun! MultiG(...) range
   let pattern = ""
   let command = ""
   for i in a:000
      if i[0] == "-"
         let pattern .= "(.*<".strpart(i,1).">)@!"
      elseif i[0] == "+"
         let pattern .= "(.*<".strpart(i,1).">)@="
      else
         let command = i
      endif
   endfor
   exe a:firstline.",".a:lastline."g/".pattern."/".command
endfun

This creates a command that allows you to automate the "regex hack". This way you could do

:G +foo -bar

to get all lines with foo and not bar. If an argument doesn't start with + or - then it is considered the command to add on to the end of the :g command. So you could also do

:G d +foo -bar

to delete the lines, or even

:G norm foXp +two foos -bar

if you escape your spaces. It also takes a range like :1,3G +etc , and you can use regex in the search terms but you must escape your spaces. Hope this helps.

---

I'm no vim wizard, but if all you want to do is "Delete lines which contain foo and do NOT contain bar" then this should do (I tried on your example file):

:v /bar/s/.*foo.*//

EDIT: actually this leaves empty lines behind. You probably want to add an optional newline to that second search pattern.

---

This is where regular expressions get a bit cumbersome. You need to use the zero width match (search_string)@= . If you want to match a list of items in any order, the search_string should start with .* (so the match starts from the start of the line each time). To match a non-occurrence, use @! instead.

I think these commands should do what you want (for clarity I am using # as the delimiter, rather than the usual / ):

Select lines which contain foo and bar:

:g#(.*foo)@=(.*bar)@=

Select lines which contain foo, bar and baz

:g#(.*foo)@=(.*bar)@=(.*baz)@=

Select lines which contain foo and do NOT contain bar

:g#(.*foo)@=(.*bar)@!

Delete lines which contain foo and bar

:g#(.*foo)@=(.*bar)@=#d

Delete lines which contain foo and do NOT contain bar

:g#(.*foo)@=(.*bar)@!#d

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