How do I parse XML in Python?

I have many rows in a database that contains xml and I'm trying to write a Python script that will go through those rows and count how many instances of a particular node attribute show up. For instance, my tree looks like:

<foo>
   <bar>
      <type foobar="1"/>
      <type foobar="2"/>
   </bar>
</foo>

How can I access the attributes 1 and 2 in the XML using Python?

---

I suggest ElementTree . There are other compatible implementations of the same API, such as lxml , and cElementTree in the Python standard library itself; but, in this context, what they chiefly add is even more speed -- the ease of programming part depends on the API, which ElementTree defines.

After building an Element instance e from the XML, eg with the XML function, or by parsing a file with something like

import xml.etree.ElementTree
e = xml.etree.ElementTree.parse('thefile.xml').getroot()

or any of the many other ways shown at ElementTree , you just do something like:

for atype in e.findall('type'):
    print(atype.get('foobar'))

and similar, usually pretty simple, code patterns.

---

minidom is the quickest and pretty straight forward:

XML:

<data>
    <items>
        <item name="item1"></item>
        <item name="item2"></item>
        <item name="item3"></item>
        <item name="item4"></item>
    </items>
</data>

PYTHON:

from xml.dom import minidom
xmldoc = minidom.parse('items.xml')
itemlist = xmldoc.getElementsByTagName('item')
print(len(itemlist))
print(itemlist[0].attributes['name'].value)
for s in itemlist:
    print(s.attributes['name'].value)

OUTPUT

4
item1
item1
item2
item3
item4

---

你可以使用BeautifulSoup

from bs4 import BeautifulSoup

x="""<foo>
   <bar>
      <type foobar="1"/>
      <type foobar="2"/>
   </bar>
</foo>"""

y=BeautifulSoup(x)
>>> y.foo.bar.type["foobar"]
u'1'

>>> y.foo.bar.findAll("type")
[<type foobar="1"></type>, <type foobar="2"></type>]

>>> y.foo.bar.findAll("type")[0]["foobar"]
u'1'
>>> y.foo.bar.findAll("type")[1]["foobar"]
u'2'

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