如何强制C＃.net应用程序在Windows中只运行一个实例？
可能重复：
创建单个实例应用程序的正确方法是什么？
如何强制C＃.net应用程序在Windows中只运行一个实例？
我更喜欢类似于以下的互斥解决方案。 正如这种方式，它重新集中在应用程序，如果它已经加载
using System.Threading;
[DllImport("user32.dll")]
[return: MarshalAs(UnmanagedType.Bool)]
static extern bool SetForegroundWindow(IntPtr hWnd);
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
bool createdNew = true;
using (Mutex mutex = new Mutex(true, "MyApplicationName", out createdNew))
{
if (createdNew)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new MainForm());
}
else
{
Process current = Process.GetCurrentProcess();
foreach (Process process in Process.GetProcessesByName(current.ProcessName))
{
if (process.Id != current.Id)
{
SetForegroundWindow(process.MainWindowHandle);
break;
}
}
}
}
}
在.net（C＃）中强制运行一个程序的一个例程在program.cs文件中使用以下代码：
public static Process PriorProcess()
// Returns a System.Diagnostics.Process pointing to
// a pre-existing process with the same name as the
// current one, if any; or null if the current process
// is unique.
{
Process curr = Process.GetCurrentProcess();
Process[] procs = Process.GetProcessesByName(curr.ProcessName);
foreach (Process p in procs)
{
if ((p.Id != curr.Id) &&
(p.MainModule.FileName == curr.MainModule.FileName))
return p;
}
return null;
}
和以下内容：
[STAThread]
static void Main()
{
if (PriorProcess() != null)
{
MessageBox.Show("Another instance of the app is already running.");
return;
}
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form());
}
这是我在我的应用程序中使用的：
static void Main()
{
bool mutexCreated = false;
System.Threading.Mutex mutex = new System.Threading.Mutex( true, @"LocalslimCODE.slimKEYS.exe", out mutexCreated );
if( !mutexCreated )
{
if( MessageBox.Show(
"slimKEYS is already running. Hotkeys cannot be shared between different instances. Are you sure you wish to run this second instance?",
"slimKEYS already running",
MessageBoxButtons.YesNo,
MessageBoxIcon.Question ) != DialogResult.Yes )
{
mutex.Close();
return;
}
}
// The usual stuff with Application.Run()
mutex.Close();
}
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