How to make my app singleton application?

This question already has an answer here:

What is the correct way to create a single-instance application? 35 answers

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Here are some good sample applications. Below is one possible way.

public static Process RunningInstance() 
{ 
    Process current = Process.GetCurrentProcess(); 
    Process[] processes = Process.GetProcessesByName (current.ProcessName); 

    //Loop through the running processes in with the same name 
    foreach (Process process in processes) 
    { 
        //Ignore the current process 
        if (process.Id != current.Id) 
        { 
            //Make sure that the process is running from the exe file. 
            if (Assembly.GetExecutingAssembly().Location.
                 Replace("/", "") == current.MainModule.FileName) 

            {  
                //Return the other process instance.  
                return process; 

            }  
        }  
    } 
    //No other instance was found, return null.  
    return null;  
}


if (MainForm.RunningInstance() != null)
{
    MessageBox.Show("Duplicate Instance");
    //TODO:
    //Your application logic for duplicate 
    //instances would go here.
}

Many other possible ways. See the examples for alternatives.

First one.

Second One.

Third One

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I think the following codes will be helpful for you. Here is the related link: http://geekswithblogs.net/chrisfalter/archive/2008/06/06/how-to-create-a-windows-form-singleton.aspx

static class Program
{
    /// <summary>
    /// The main entry point for the application.
    /// </summary>
    [STAThread]
    static void Main()
    {
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);

        /*====================================================
         * 
         * Add codes here to set the Winform as Singleton
         * 
         * ==================================================*/
        bool mutexIsAvailable = false;

        Mutex mutex = null;

        try
        {
            mutex = new Mutex(true, "SampleOfSingletonWinForm.Singleton");
            mutexIsAvailable = mutex.WaitOne(1, false); // Wait only 1 ms
        }
        catch (AbandonedMutexException)
        {
            // don't worry about the abandonment; 
            // the mutex only guards app instantiation
            mutexIsAvailable = true;
        }

        if (mutexIsAvailable)
        {
            try
            {
                Application.Run(new SampleOfSingletonWinForm());
            }
            finally
            {
                mutex.ReleaseMutex();
            }
        }

        //Application.Run(new SampleOfSingletonWinForm());
    }
}

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The approach I know of is the following. The program must attempt to open a named mutex. If that mutex existed, then exit, otherwise, create the mutex. But this seems to contradict your condition that "its another instance does not exit at the run time". Anyway, maybe this too was helpful

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