How to check if a process is running via a batch script
How can I check if an application is running from a batch (well cmd) file?
I need to not launch another instance if a program is already running. (I can't change the app to make it single instance only.)
Also the application could be running as any user.
Another possibility I came up with, inspired by using grep, is:
tasklist /FI "IMAGENAME eq myapp.exe" 2>NUL | find /I /N "myapp.exe">NUL
if "%ERRORLEVEL%"=="0" echo Program is running
It doesn't need to save an extra file, so I prefer this method.
Here's how I've worked it out:
tasklist /FI "IMAGENAME eq notepad.exe" /FO CSV > search.log
FOR /F %%A IN (search.log) DO IF %%~zA EQU 0 GOTO end
start notepad.exe
:end
del search.log
The above will open Notepad if it is not already running.
Edit: Note that this won't find applications hidden from the tasklist. This will include any scheduled tasks running as a different user, as these are automatically hidden.
I like Chaosmaster's solution! But I looked for a solution which does not start another external program (like find.exe or findstr.exe). So I added the idea from Matt Lacey's solution, which creates an also avoidable temp file. At the end I could find a fairly simple solution, so I share it...
SETLOCAL EnableExtensions
set EXE=myprog.exe
FOR /F %%x IN ('tasklist /NH /FI "IMAGENAME eq %EXE%"') DO IF %%x == %EXE% goto FOUND
echo Not running
goto FIN
:FOUND
echo Running
:FIN
This is working for me nicely...
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