用java解析这个xml文件

这个问题在这里已经有了答案：

这是在Java中解析XML的最佳库[关闭] 7个答案

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public static void main(String[] args) throws MarshalException,
ValidationException, ParserConfigurationException, SAXException,
IOException {

    File fXmlFile = new File(
            "/home/Parsing/src/com/parsing/test.xml");
    DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
    DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
    Document doc = dBuilder.parse(fXmlFile);

    doc.getDocumentElement().normalize();

    Node node = doc.getDocumentElement().getParentNode();

    System.out.println(doc.getDocumentElement().getNodeName());

    NodeList itemList = node.getChildNodes();
    for (int i = 0; i < itemList.getLength(); i++) {

        Node nNode = itemList.item(i);

        System.out.println("Current Element : " + nNode.getNodeName());

        getChildNode(nNode.getChildNodes());

    }
}

private static void getChildNode(NodeList childNodes) {   // This method is going to retrieve the child nodes
    // TODO Auto-generated method stub
    System.out.println(childNodes.getLength());

    for (int i = 1; i < childNodes.getLength(); i++) {
        Node cNode = childNodes.item(i);

        System.out.println(cNode.getNodeName());
        /**
         * This will get the attribute of the node 
         */
        if (cNode.hasAttributes()) {

            NamedNodeMap nodeMap = cNode.getAttributes();
            for (int f = 0; f < nodeMap.getLength(); f++) {
                System.out.println("Att " + nodeMap.item(f).getNodeName()
                        + " " + nodeMap.item(f).getNodeValue());
            }
        }

        if (cNode.hasChildNodes()) {

            // For getting the value if node has more than 2 or atleast two childs

            if (cNode.getChildNodes().getLength() >= 2) {

                getChildNode(cNode.getChildNodes());
            }

            // For getting the node has no childs and it contains text node value

            else if (cNode.getNodeType() == cNode.ELEMENT_NODE) {

                Element ele = (Element) cNode;
                System.out.println("t" + ele.getTextContent());

            }
        }

        i++;
    }
}

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一种方法是通过评估字符串手动执行。 另一种方法是使用所有可用的Java XML库之一... http://en.wikipedia.org/wiki/Java_API_for_XML_Processing

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答案是针对解析器类型的。 如果你打算使用DOM解析器，可能这会有所帮助。 这些是SAX解析器的例子。

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