How can I wrap a synchronous function in an async coroutine?

I'm using aiohttp to build an API server that sends TCP requests off to a seperate server. The module that sends the TCP requests is synchronous and a black box for my purposes. So my problem is that these requests are blocking the entire API. I need a way to wrap the module requests in an asynchronous coroutine that won't block the rest of the API.

So, just using sleep as a simple example, is there any way to somehow wrap time-consuming synchronous code in a non-blocking coroutine, something like this:

async def sleep_async(delay):
    # After calling sleep, loop should be released until sleep is done
    yield sleep(delay)
    return 'I slept asynchronously'

---

Eventually I found an answer in this thread. The method I was looking for is run_in_executor. This allows a synchronous function to be run asynchronously without blocking an event loop.

In the sleep example I posted above, it might look like this:

import asyncio
from time import sleep
from concurrent.futures import ProcessPoolExecutor

async def sleep_async(loop, delay):
    # Can set executor to None if a default has been set for loop
    await loop.run_in_executor(ProcessPoolExecutor(), sleep, delay)
    return 'I slept asynchronously'

Also see the following answer -> How do we call a normal function where a coroutine is expected?

链接地址: http://www.djcxy.com/p/53228.html

上一篇: 基于它是否被再次调用，在协程中有条件？

下一篇: 如何在异步协程中包装同步函数？