Accessing a class' member variables in Python?
class Example(object):
def the_example(self):
itsProblem = "problem"
theExample = Example()
print(theExample.itsProblem)
How do I access a class's variable? I've tried adding this definition:
def return_itsProblem(self):
return itsProblem
Yet, that fails also.
The answer, in a few words
In your example, itsProblem is a local variable.
Your must use self to set and get instance variables. You can set it in the __init__ method. Then your code would be:
class Example(object):
def __init__(self):
self.itsProblem = "problem"
theExample = Example()
print(theExample.itsProblem)
But if you want a true class variable, then use the class name directly:
class Example(object):
itsProblem = "problem"
theExample = Example()
print(theExample.itsProblem)
print (Example.itsProblem)
But be careful with this one, as theExample.itsProblem is automatically set to be equal to Example.itsProblem , but is not the same variable at all and can be changed independently.
Some explanations
In Python, variables car be created dynamically. Therefor, you can do the following:
class Example(object):
pass
Example.itsProblem = "problem"
e = Example()
e.itsSecondProblem = "problem"
print Example.itsProblem == e.itsSecondProblem
Prints
True
Therefore, that's exactly what you do with the previous examples.
Indeed, in Python we use self as this , but it's a bit more than that. Self is the the first argument to any object method because the first argument is always the object reference. This is automatic, whether you call it self or not.
Which means you can do:
class Example(object):
def __init__(self):
self.itsProblem = "problem"
theExample = Example()
print(theExample.itsProblem)
Or:
class Example(object):
def __init__(my_super_self):
my_super_self.itsProblem = "problem"
theExample = Example()
print(theExample.itsProblem)
It's exactly the same. The first argument of ANY object method is the current object, we only call it self as a convention. And you add just a variable to this object, the same way you would do it from outside.
Now, about the class variables.
When you do:
class Example(object):
itsProblem = "problem"
theExample = Example()
print(theExample.itsProblem)
You'll notice we first set a class variable , then we access an object (instance) variable . We never set this object variable but it works, how is that possible?
Well, Python tries to get first the object variable, but if it can't find it, will give you the class variable. Warning: the class variable is shared among instances, and the object variable is not.
As a conclusion, never use class variables to set default values to object variables. Use __init__ for that.
Eventually, you will learn that Python classes are instances and therefore objects themselves, which gives new insight to understanding the above. Come back and read this again later, once you realize that.
You are declaring a local variable, not a class variable. To set an instance variable (attribute), use
class Example(object):
def the_example(self):
self.itsProblem = "problem" # <-- remember the 'self.'
theExample = Example()
theExample.the_example()
print(theExample.itsProblem)
To set a class variable (aka static member), use
class Example(object):
def the_example(self):
Example.itsProblem = "problem"
# or, type(self).itsProblem = "problem"
# depending what you want to do when the class is derived.
If you have an instance function (ie one that gets passed self) you can use self to get a reference to the class using self.__ __class__ __
For example in the code below tornado creates an instance to handle get requests, but we can get hold of the get_handler class and use it to hold a riak client so we do not need to create one for every request.
import tornado.web
import riak
class get_handler(tornado.web.requestHandler):
riak_client = None
def post(self):
cls = self.__class__
if cls.riak_client is None:
cls.riak_client = riak.RiakClient(pb_port=8087, protocol='pbc')
# Additional code to send response to the request ...
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