Is there a short contains function for lists?

我看到人们正在使用any来收集另一个列表来查看一个项目是否存在于一个列表中，但是有一个快速的方法可以做到吗？：

if list.contains(myItem):
    # do something

---

You can use this syntax:

if myItem in list:
    # do something

Also, inverse operator:

if myItem not in list:
    # do something

It's work fine for lists, tuples, sets and dicts (check keys).

Note that this is an O(n) operation in lists and tuples, but an O(1) operation in sets and dicts.

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In addition to what other have said, you may also be interested to know that what in does is to call the list.__contains__ method, that you can define on any class you write and can get extremely handy to use python at his full extent.

A dumb use may be:

>>> class ContainsEverything:
    def __init__(self):
        return None
    def __contains__(self, *elem, **k):
        return True


>>> a = ContainsEverything()
>>> 3 in a
True
>>> a in a
True
>>> False in a
True
>>> False not in a
False
>>>         

---

The list method index will return -1 if the item is not present, and will return the index of the item in the list if it is present. Alternatively in an if statement you can do the following:

if myItem in list:
    #do things

You can also check if an element is not in a list with the following if statement:

if myItem not in list:
    #do things

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