fopen() returning a NULL pointer, but the file definitely exists
The code I have is as follows:
FILE *txt_file = fopen("data.txt", "r");
if (txt_file == NULL) {
perror("Can't open file");
}
The error message returned is:
Can't open file: No such file or directory
The file 'data.txt' definitely exists in the working directory (it exists in the directory that contains my .c and .h files), so why is fopen() is returning a NULL pointer?
Is it possible that the filename is not really "data.txt"?
On Unix, filenames are really byte strings not character strings, and it is possible to create files with controls such as backspace in their names. I have seen cases in the past in which copy-pasting into terminals resulted in files with ordinary-looking names, but trying to open the filename that appears in a directory listing results in an error.
One way to tell for sure that the filenames really are what you think they are:
$ python
>>> import os
>>> os.listdir('.')
Standard problem. Try
FILE *txt_file = fopen("C:SomeFolderdata.txt", "r");
Ie try opening it with the full absolute path first ; if it works then you just have to figure out what the current directory is with _getcwd() and then fix your relative path.
Make sure that your input file is in the same directory as the executable, which may be different than the one where your source files are kept. If you're running the program in an IDE debugger, make sure that your working directory is set to the location of the input file. Also, if you're running in *nix rather than Windows, you may need to prepend a "./" to the input filename.
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