catching an IOError in python

I wrote a method that does some stuff and catches bad filenames. what should happen is if the path doesn't exist, it throws an IOError. however, it thinks my exception handling is bad syntax... why??

def whatever():
    try:
        # do stuff
        # and more stuff
    except IOError:
        # do this
        pass
whatever()

but before it even gets to calling whatever() , it prints the following:

Traceback (most recent call last):
  File "", line 1, in 
  File "getquizzed.py", line 55
    except IOError:
         ^
SyntaxError: invalid syntax

when imported...help?!

---

Check your indenting. This unhelpful SyntaxError error has fooled me before. :)

---

只是在你的try块中缺少某些东西，例如pass或其他东西，否则会产生缩进错误。

---

there's 1 more possible if you're privileged to have an older installation

and

you're using the 'as' syntax:

except IOError as ioe:

and

the parser's getting tripped up on 'as'.

Using as is the preferred syntax in Python 2.6 and better.

It's a syntax error in Python 2.5 and older. For pre-2.6, use this:

except IOError, ioe:

链接地址: http://www.djcxy.com/p/54690.html

上一篇: 如何在Python中更改目录（cd）？

下一篇: 在Python中捕获IOError