get script directory name

2018-06-19 10:19:30

I know I can use this to get the full file path

os.path.dirname(os.path.realpath(__file__))

But I want just the name of the folder, my scrip is in. SO if I have my_script.py and it is located at

/home/user/test/my_script.py

I want to return "test" How could I do this?

Thanks

import os
os.path.basename(os.path.dirname(os.path.realpath(__file__)))

分解：

currentFile = __file__  # May be 'my_script', or './my_script' or
                        # '/home/user/test/my_script.py' depending on exactly how
                        # the script was run/loaded.
realPath = os.path.realpath(currentFile)  # /home/user/test/my_script.py
dirPath = os.path.dirname(realPath)  # /home/user/test
dirName = os.path.basename(dirPath) # test

>>> import os
>>> os.getcwd()

Just write

import os
import os.path
print( os.path.basename(os.getcwd()) )

Hope this helps...

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