Python：从字符串名称中调用一个函数
这个问题在这里已经有了答案：
如果它在一个类中，则可以使用getattr：
class MyClass(object):
def install(self):
print "In install"
method_name = 'install' # set by the command line options
my_cls = MyClass()
method = None
try:
method = getattr(my_cls, method_name)
except AttributeError:
raise NotImplementedError("Class `{}` does not implement `{}`".format(my_cls.__class__.__name__, method_name))
method()
或者如果它是一个功能：
def install():
print "In install"
method_name = 'install' # set by the command line options
possibles = globals().copy()
possibles.update(locals())
method = possibles.get(method_name)
if not method:
raise NotImplementedError("Method %s not implemented" % method_name)
method()
你也可以使用字典。
def install():
print "In install"
methods = {'install': install}
method_name = 'install' # set by the command line options
if method_name in methods:
methods[method_name]() # + argument list of course
else:
raise Exception("Method %s not implemented" % method_name)
为什么不能使用eval（）？
def install():
print "In install"
新方法
def installWithOptions(var1, var2):
print "In install with options " + var1 + " " + var2
然后你调用下面的方法
method_name1 = 'install()'
method_name2 = 'installWithOptions("a","b")'
eval(method_name1)
eval(method_name2)
这给出了输出
In install
In install with options a b