如何从回调函数创建返回承诺的函数
这个问题在这里已经有了答案:
这个想法并不是在回调中创建并返回promise,而是在外部函数中创建它(可以return
它),并且只解析回调中的承诺:
myFunction():Promise<any>{
return new Promise(resolve => {
libapi.callnetwork(arg1, callback(data){
resolve(data);
});
});
}
或干脆
myFunction():Promise<any>{
return new Promise(resolve => {
libapi.callnetwork(arg1, resolve);
});
}
香草,抢解析功能
let myFunction = () => {
let resolve;
let promise = new Promise(r => resolve = r);
libapi.callnetwork(arg1, resolve);
return promise;
};
myFunction():Promise<any>{
let resolveFn = (data) => data;
libapi.callnetwork(arg1, resolveFn);
return new Promise(resolveFn);
}
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