Gulp + babelify + browserify issue
I'm trying to create a gulp task with browserify and babelify. Here is the task:
var gulp = require('gulp');
var browserify = require('gulp-browserify');
var source = require('vinyl-source-stream');
var babelify = require('babelify');
gulp.task('js', function () {
browserify('./resources/js/*.js')
.transform(babelify)
.bundle()
.pipe(source('*.js'))
.pipe(gulp.dest('./public/js'));
});
I found a few sample code, tried to use them, but the result was always the same.
When i run the task, and save my example.js file, the following error occurs:
TypeError: browserify(...).transform is not a function
What am I doing wrong?
You're mixing up the API for browserify and gulp-browserify .
From the gulp-browserify docs, you'll want to do something like this:
var gulp = require('gulp')
var browserify = require('gulp-browserify')
gulp.task('js', function () {
gulp.src('./resources/js/*.js')
.pipe(browserify({
transform: ['babelify'],
}))
.pipe(gulp.dest('./public/js'))
});
EDIT: Since this question was first answered, gulp-browserify has been abandoned and gulp has evolved a great deal. If you'd like to achieve the same thing with a newer version of gulp, you can follow the guides provided by the gulp team.
You'll end up with something like the following:
var browserify = require('browserify');
var babelify = require('babelify');
var gulp = require('gulp');
var source = require('vinyl-source-stream');
var buffer = require('vinyl-buffer');
var sourcemaps = require('gulp-sourcemaps');
var util = require('gulp-util');
gulp.task('default', function () {
var b = browserify({
entries: './resources/test.js',
debug: true,
transform: [babelify.configure({
presets: ['es2015']
})]
});
return b.bundle()
.pipe(source('./resources/test.js'))
.pipe(buffer())
.pipe(sourcemaps.init({ loadMaps: true }))
// Add other gulp transformations (eg. uglify) to the pipeline here.
.on('error', util.log)
.pipe(sourcemaps.write('./'))
.pipe(gulp.dest('./public/js/'));
});