How do you normalize a file path in Bash?
I want to transform /foo/bar/..
to /foo
Is there a bash command which does this?
Edit: in my practical case, the directory does exist.
if you're wanting to chomp part of a filename from the path, "dirname" and "basename" are your friends, and "realpath" is handy too.
dirname /foo/bar/baz
# /foo/bar
basename /foo/bar/baz
# baz
dirname $( dirname /foo/bar/baz ))
# /foo
realpath ../foo
# ../foo: No such file or directory
realpath /tmp/../tmp/../tmp
# /tmp
Edit
Realpath appears not to be standard issue.
The closest you can get with the stock standard is
readlink -f /path/here/..
Realpath appears to come from debian, and is not part of coreutils: http://packages.debian.org/unstable/utils/realpath Which was originally part of the DWWW package.
( also available on gentoo as app-admin/realpath )
readlink -m /path/there/../../
Works the same as
realpath -s /path/here/../../
in that it doesn't need the path to actually exist to normalise it.
I don't know if there is a direct bash command to do this, but I usually do
normalDir="`cd "${dirToNormalize}";pwd`"
echo "${normalDir}"
and it works well.
Try realpath
. Below is the source in its entirety, hereby donated to the public domain.
// realpath.c: display the absolute path to a file or directory.
// Adam Liss, August, 2007
// This program is provided "as-is" to the public domain, without express or
// implied warranty, for any non-profit use, provided this notice is maintained.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <libgen.h>
#include <limits.h>
static char *s_pMyName;
void usage(void);
int main(int argc, char *argv[])
{
char
sPath[PATH_MAX];
s_pMyName = strdup(basename(argv[0]));
if (argc < 2)
usage();
printf("%sn", realpath(argv[1], sPath));
return 0;
}
void usage(void)
{
fprintf(stderr, "usage: %s PATHn", s_pMyName);
exit(1);
}
链接地址: http://www.djcxy.com/p/56734.html
上一篇: “猫”EOF“如何在bash中工作?
下一篇: 你如何规范Bash中的文件路径?