Extract file basename without path and extension in bash
This question already has an answer here:
You don't have to call the external basename command. Instead, you could use the following commands:
$ s=/the/path/foo.txt
$ echo ${s##*/}
foo.txt
$ s=${s##*/}
$ echo ${s%.txt}
foo
$ echo ${s%.*}
foo
Note that this solution should work in all recent (post 2004) POSIX compliant shells, (eg bash , dash , ksh , etc.).
Source: Shell Command Language 2.6.2 Parameter Expansion
More on bash String Manipulations: http://tldp.org/LDP/LG/issue18/bash.html
The basename command has two different invocations; in one, you specify just the path, in which case it gives you the last component, while in the other you also give a suffix that it will remove. So, you can simplify your example code by using the second invocation of basename. Also, be careful to correctly quote things:
fbname=$(basename "$1" .txt) echo "$fbname"
A combination of basename and cut works fine, even in case of double ending like .tar.gz :
fbname=$(basename "$fullfile" | cut -d. -f1)
Would be interesting if this solution needs less arithmetic power than Bash Parameter Expansion.
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