Print single quotes in shell script using option

 

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  • How to escape single quotes within single quoted strings? 19 answers

    • You can't nest single quotes in bash, so the line is interpreted as 

    /bin/bash -l -c 'echo "'John'"'
                |......| ---------- single quoted
                       |....| ----- not quoted
                            |.| --- quoted

    So, properly escape the single quotes: 

    /bin/bash -c 'echo "'''John'''"'

    or, if the string in single quotes is really simple, 

    /bin/bash -c 'echo "''John''"'

    尝试删除双引号并转义单引号： 

    /bin/bash -l -c "echo 'John'"

    A common workaround is to use printf so you don't need to use literal single quotes in the format string. 

    bash -l -c 'printf "x27Johnx27n"'

    (Using bash -l here is probably misdirected and nonportable.)

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