从他们的知识产权获取访问国家
我想通过他们的IP获取访问者国家...现在我使用这个（http：//api.hostip.info/country.php？ip = ......）
这是我的代码：
<?php
if (isset($_SERVER['HTTP_CLIENT_IP']))
{
$real_ip_adress = $_SERVER['HTTP_CLIENT_IP'];
}
if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
{
$real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
$real_ip_adress = $_SERVER['REMOTE_ADDR'];
}
$cip = $real_ip_adress;
$iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip;
$creatorlocation = file_get_contents($iptolocation);
?>
嗯，它工作正常，但事情是，这会返回像美国或CA这样的国家代码，而不是像美国或加拿大这样的全国名称。
那么，hostip.info提供这个选择吗？
我知道我可以写一些代码，最终将这两个字母转换为全国名字，但我懒得写一个包含所有国家的代码......
PS：出于某种原因，我不想使用任何现成的CSV文件或任何可以为我获取此信息的代码，例如ip2country现成的代码和CSV。
试试这个简单的PHP函数。
<?php
function ip_info($ip = NULL, $purpose = "location", $deep_detect = TRUE) {
$output = NULL;
if (filter_var($ip, FILTER_VALIDATE_IP) === FALSE) {
$ip = $_SERVER["REMOTE_ADDR"];
if ($deep_detect) {
if (filter_var(@$_SERVER['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP))
$ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
if (filter_var(@$_SERVER['HTTP_CLIENT_IP'], FILTER_VALIDATE_IP))
$ip = $_SERVER['HTTP_CLIENT_IP'];
}
}
$purpose = str_replace(array("name", "n", "t", " ", "-", "_"), NULL, strtolower(trim($purpose)));
$support = array("country", "countrycode", "state", "region", "city", "location", "address");
$continents = array(
"AF" => "Africa",
"AN" => "Antarctica",
"AS" => "Asia",
"EU" => "Europe",
"OC" => "Australia (Oceania)",
"NA" => "North America",
"SA" => "South America"
);
if (filter_var($ip, FILTER_VALIDATE_IP) && in_array($purpose, $support)) {
$ipdat = @json_decode(file_get_contents("http://www.geoplugin.net/json.gp?ip=" . $ip));
if (@strlen(trim($ipdat->geoplugin_countryCode)) == 2) {
switch ($purpose) {
case "location":
$output = array(
"city" => @$ipdat->geoplugin_city,
"state" => @$ipdat->geoplugin_regionName,
"country" => @$ipdat->geoplugin_countryName,
"country_code" => @$ipdat->geoplugin_countryCode,
"continent" => @$continents[strtoupper($ipdat->geoplugin_continentCode)],
"continent_code" => @$ipdat->geoplugin_continentCode
);
break;
case "address":
$address = array($ipdat->geoplugin_countryName);
if (@strlen($ipdat->geoplugin_regionName) >= 1)
$address[] = $ipdat->geoplugin_regionName;
if (@strlen($ipdat->geoplugin_city) >= 1)
$address[] = $ipdat->geoplugin_city;
$output = implode(", ", array_reverse($address));
break;
case "city":
$output = @$ipdat->geoplugin_city;
break;
case "state":
$output = @$ipdat->geoplugin_regionName;
break;
case "region":
$output = @$ipdat->geoplugin_regionName;
break;
case "country":
$output = @$ipdat->geoplugin_countryName;
break;
case "countrycode":
$output = @$ipdat->geoplugin_countryCode;
break;
}
}
}
return $output;
}
?>
如何使用：
示例1：获取访问者IP地址的详细信息
<?php
echo ip_info("Visitor", "Country"); // India
echo ip_info("Visitor", "Country Code"); // IN
echo ip_info("Visitor", "State"); // Andhra Pradesh
echo ip_info("Visitor", "City"); // Proddatur
echo ip_info("Visitor", "Address"); // Proddatur, Andhra Pradesh, India
print_r(ip_info("Visitor", "Location")); // Array ( [city] => Proddatur [state] => Andhra Pradesh [country] => India [country_code] => IN [continent] => Asia [continent_code] => AS )
?>
示例2：获取任何IP地址的详细信息。 [支持IPV4和IPV6]
<?php
echo ip_info("173.252.110.27", "Country"); // United States
echo ip_info("173.252.110.27", "Country Code"); // US
echo ip_info("173.252.110.27", "State"); // California
echo ip_info("173.252.110.27", "City"); // Menlo Park
echo ip_info("173.252.110.27", "Address"); // Menlo Park, California, United States
print_r(ip_info("173.252.110.27", "Location")); // Array ( [city] => Menlo Park [state] => California [country] => United States [country_code] => US [continent] => North America [continent_code] => NA )
?>
您可以使用http://www.geoplugin.net/提供的简单API
$xml = simplexml_load_file("http://www.geoplugin.net/xml.gp?ip=".getRealIpAddr());
echo $xml->geoplugin_countryName ;
echo "<pre>";
foreach ($xml as $key => $value)
{
echo $key , "= " , $value , " n" ;
}
echo "</pre>";
使用的功能
function getRealIpAddr()
{
if (!empty($_SERVER['HTTP_CLIENT_IP'])) //check ip from share internet
{
$ip=$_SERVER['HTTP_CLIENT_IP'];
}
elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) //to check ip is pass from proxy
{
$ip=$_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
$ip=$_SERVER['REMOTE_ADDR'];
}
return $ip;
}
产量
United States
geoplugin_city= San Antonio
geoplugin_region= TX
geoplugin_areaCode= 210
geoplugin_dmaCode= 641
geoplugin_countryCode= US
geoplugin_countryName= United States
geoplugin_continentCode= NA
geoplugin_latitude= 29.488899230957
geoplugin_longitude= -98.398696899414
geoplugin_regionCode= TX
geoplugin_regionName= Texas
geoplugin_currencyCode= USD
geoplugin_currencySymbol= $
geoplugin_currencyConverter= 1
它让你有很多选择可以玩
谢谢
:)
我试过Chandra的答案，但我的服务器配置不允许file_get_contents（）
PHP Warning: file_get_contents() URL file-access is disabled in the server configuration
我修改了Chandra的代码，以便它也适用于使用cURL的服务器：
function ip_visitor_country()
{
$client = @$_SERVER['HTTP_CLIENT_IP'];
$forward = @$_SERVER['HTTP_X_FORWARDED_FOR'];
$remote = $_SERVER['REMOTE_ADDR'];
$country = "Unknown";
if(filter_var($client, FILTER_VALIDATE_IP))
{
$ip = $client;
}
elseif(filter_var($forward, FILTER_VALIDATE_IP))
{
$ip = $forward;
}
else
{
$ip = $remote;
}
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.geoplugin.net/json.gp?ip=".$ip);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$ip_data_in = curl_exec($ch); // string
curl_close($ch);
$ip_data = json_decode($ip_data_in,true);
$ip_data = str_replace('"', '"', $ip_data); // for PHP 5.2 see stackoverflow.com/questions/3110487/
if($ip_data && $ip_data['geoplugin_countryName'] != null) {
$country = $ip_data['geoplugin_countryName'];
}
return 'IP: '.$ip.' # Country: '.$country;
}
echo ip_visitor_country(); // output Coutry name
?>
希望有帮助;-)
链接地址: http://www.djcxy.com/p/57535.html