&& and 'and' are the same in php?
This question already has an answer here:
They do not have the same precedence. Fully parenthesised, your code is:
($keyWord = 2) and (3>4); // $keyWord = 2
$symbol = (2 && (3>4)); // $symbol = false
2
and false
are clearly not the same, hence 'not-equal'
.
More on operator precedence
Well, altering the code slightly to:
<?php
$keyWord = 2 and 3>4;
$symbol = 2 && 3>4;
var_dump($keyWord);
var_dump($symbol);
?>
produces an output of:
int(2) bool(false)
As Kolink points out above, this is due to operator precedence.
Here is the precedence of logical operators (part of the table)
left && logical
left || logical
left ? : ternary
right = += -= *= /= .= %= &= |= ^= <<= >>= => assignment
left and
In your case :
case 1:
$keyWord = 2 and 3>4;
($keyWord = 2) and (3>4);
Here $keyWord = 2
case 2:
$symbol = 2 && 3>4;
$symbol = (2 && (3>4));
Here $symbol = false
Solution : $keyWord = (2 and (3>4));
and $symbol = 2 && (3>4);
Use brackets
Ref: http://php.net/manual/en/language.operators.precedence.php
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