1 > false) returns true?

 

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  • Type-juggling and (strict) greater/lesser-than comparisons in PHP 3 answers

    • In this case it's -1 that is converted into boolean ( true , as only 0 is treated as false ). So the final comparison is 

    if (true > false) {
    ...
}

    Type Juggling can be very unintuitive, so always try to avoid situations where you compare variables of two different types. In case of equality comparison always try to use identity operator ( === ), in case of inequality all you can do is to add a manual cast.

    See also: http://us3.php.net/manual/en/types.comparisons.php

    Please see PHP Comparision Operators - table Comparison with Various Types 

    Type of Operand 1   Type of Operand 2       Result
bool or null        anything                Convert both sides to bool, FALSE < TRUE

    So if you compare bool to anything else, then the second operand is casted to boolean true. Also we have information here, that FALSE < TRUE , what exactly happens in your example.

    <是一个数字比较运算符，代码没有宽松比较，将-1转换为真，从而得到结果。

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