Type Juggling and Booleans
I've been reading the PHP Docs on Type Juggling and Booleans but I still don't understand why this comparison evaluates as true. My [incorrect] understanding tells me that in the below if statement, the integer 0 is considered FALSE and "a", being a non-empty string is considered TRUE. Therefore, I expected this comparison to resolve to FALSE == TRUE and ultimately, FALSE. Which part did I get wrong?
<?php
if(0 == "a"){
$result = "TRUE";
}else{
$result = "FALSE";
}
//$result == "TRUE"
?>
http://codepad.viper-7.com/EjxBF5
When PHP does a string <=> integer comparison, it attempts to convert the string to a number in an intelligent way. The assumption is that if you have a string "42" then you want to compare the value 42 to the other integer. When the string doesn't start with numbers, then its value is zero.
From the docs:
The value is given by the initial portion of the string. If the string starts with valid numeric data, this will be the value used. Otherwise, the value will be 0 (zero).
This behavior is also inferred in the comparison docs (look at the first line in the first example).
Your mistake is that you assume operator ==
coerces each of its operands to boolean before comparing them. It does no such thing.
What happens is that since you are comparing an integer to a string, the string is converted to an integer (in this case "a" converts to 0
) and then the comparison 0 == 0
is performed.
It will work if you use a strict comparison ===
instead of ==
. The strict comparison also checks the type of the variables, so 0 === 'a'
would be false.
上一篇: 总是C扩展(即使在PyPy上)?
下一篇: 类型杂耍和布尔人