replace first and last occurrence of a character

2018-06-21 04:34:43

I need a regex for so as to convert the string {somestr} to :somestr , but I need to replace only the first and the last occurrences of curly braces, since if there is any occurrence in the middle of a string - it should not be removed.

So far I have tried:

the incoming string var path = '/claims/{id}'

var pathWithoutBraces = path.replace("{", ":").replace("}", "")

The output is /claims/:id which is what expected, but still it will replace all the further occurences in the whole string

您可以使用以下内容替换第一个和最后一个{和}

var s='/claims/{abc{de}}f}';

document.write(s.replace(/{(.*)}/,':$1'));

这应该只取代第一个和最后一个大括号：

str.replace(/({)(.*)(})/, ':$2');

How about: /({)([}w]+)(})/ ? See https://regex101.com/r/pW4fU7/2

This will demand and capture an opening and closing curly bracket, and also will capture word characters (and closing curly brackets) in between. Here's a snippet for your example:

var path = '/claims/{id}';
document.write(path.replace(/({)([}w]+)(})/,':$2'));

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