PHP语法$ {“field”}

这个问题在这里已经有了答案:

  • 在PHP 5中的字符串大括号的答案

  • 它被称为Complex (curly) syntax

    这不称为复杂的,因为它的语法很复杂,但是因为它允许使用复杂的表达式。

    任何具有字符串表示的标量变量,数组元素或对象属性均可通过此语法包含在内。 简单地写出表达式的方式与字符串外部的方式相同,然后将其包装在{和}中。 由于{不能被转义,这个语法只有在$紧跟在{之后才能被识别。 使用{ $获取文字{$。 一些例子要说清楚:

    <?php
    // Show all errors
    error_reporting(E_ALL);
    
    $great = 'fantastic';
    
    // Won't work, outputs: This is { fantastic}
    echo "This is { $great}";
    
    // Works, outputs: This is fantastic
    echo "This is {$great}";
    echo "This is ${great}";
    
    // Works
    echo "This square is {$square->width}00 centimeters broad."; 
    
    
    // Works, quoted keys only work using the curly brace syntax
    echo "This works: {$arr['key']}";
    
    
    // Works
    echo "This works: {$arr[4][3]}";
    
    // This is wrong for the same reason as $foo[bar] is wrong  outside a string.
    // In other words, it will still work, but only because PHP first looks for a
    // constant named foo; an error of level E_NOTICE (undefined constant) will be
    // thrown.
    echo "This is wrong: {$arr[foo][3]}"; 
    
    // Works. When using multi-dimensional arrays, always use braces around arrays
    // when inside of strings
    echo "This works: {$arr['foo'][3]}";
    
    // Works.
    echo "This works: " . $arr['foo'][3];
    
    echo "This works too: {$obj->values[3]->name}";
    
    echo "This is the value of the var named $name: {${$name}}";
    
    echo "This is the value of the var named by the return value of getName(): {${getName()}}";
    
    echo "This is the value of the var named by the return value of $object->getName(): {${$object->getName()}}";
    
    // Won't work, outputs: This is the return value of getName(): {getName()}
    echo "This is the return value of getName(): {getName()}";
    ?>
    
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