在AutoMapper中将复杂类型映射到平面类型
我有一个复杂的对象,如:
public class BusinessUnit
{
public TradingDesk TradingDesk { get; }
public string Division { get; }
public BusinessUnit(string division, TradingDesk tradingDesk)
{
Division = division;
TradingDesk = tradingDesk;
}
}
我想将其映射到平面类型:
public class Row
{
//TradingDesk properties
public string TraderFirstName { get; set; }
public string TraderLastName { get; set; }
public string TradingDeskName { get; set; }
public string Division { get; set; }
}
我已经为TradingDesk
配置了AutoMapper
:
CreateMap<TradingDesk, Row>().ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.Name));
所以下面的测试通过:
[Test]
public void Should_Map_TradingDesk_To_Row()
{
var tradingDesk = Fixture.Create<TradingDesk>();
var mapped = AutoMapper.Map<Row>(tradingDesk);
mapped.TradingDeskName.Should()
.Be(tradingDesk.Name);
mapped.TraderFirstName.Should()
.Be(tradingDesk.Trader.FirstName);
mapped.TraderLastName.Should()
.Be(tradingDesk.Trader.LastName);
}
但是,当我尝试映射BusinessUnit
来Row
,我不得不重新AutoMapper
为TradingDesk
这样:
CreateMap<BusinessUnit, Row>()
.ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.TradingDesk.Name))
.ForMember(vm => vm.TraderFirstName, op => op.MapFrom(src => src.TradingDesk.Trader.FirstName))
.ForMember(vm => vm.TraderLastName, op => op.MapFrom(src => src.TradingDesk.Trader.LastName));
我期望AutoMapper
在映射BusinessUnit
时需要将TradingDesk
映射到Row
时,应使用已配置的源和目标类型映射。 通过这种方式,我可以构建从最小型到最大型的配置,同时展平复杂的对象,而无需为扁平类型中的每个单独成员定义映射。
实际的语法可能会有所不同,因为我以静态的方式使用AutoMapper,但原理保持不变:
Mapper.CreateMap<BusinessUnit, Row>()
.ConvertUsing(source => Mapper.Map<TradingDesk, Row>(source.TradingDesk));
首先,我认为你的交易平台地图只是
CreateMap<TradingDesk, Row>();
如果内存为我提供了正确的服务,因为您的目标成员在“。”时匹配源成员名称。 被删除,那么你不需要明确指定它。
如果你改变你的Row类到这个
public class Row
{
//TradingDesk properties
public string TradingDeskTraderFirstName { get; set; }
public string TradingDeskTraderLastName { get; set; }
public string TradingDeskName { get; set; }
public string Division { get; set; }
}
你的地图会是
CreateMap<BusinessUnit, Row>();
如果你永远不会映射到TradingDesk,那么删除该地图。
如果这是在一些配置文件中定义的,你也可以说
RecognizePrefixes("TradingDesk");
然后你不需要改变你的Row类。
如果您不想创建特殊的转换器或属性解析器,则可以在主对象的映射之后执行第二个映射,例如:
Mapper.Initialize(cfg =>
{
cfg.CreateMap<TradingDesk, Row>()
.ForMember(vm => vm.TradingDeskName, op => op.MapFrom(src => src.Name));
cfg.CreateMap<BusinessUnit, Row>()
.AfterMap((businessUnit, row) => { Mapper.Map(businessUnit.TradingDesk, row); });
});
var source = new BusinessUnit("division", new TradingDesk { TraderFirstName = "FirstName", TraderLastName = "LastName", Name = "DeskName" });
var dest = Mapper.Map<Row>(source);
在这种情况下,该对象已被映射而不创建新的实例。
链接地址: http://www.djcxy.com/p/6381.html上一篇: Map complex type to flat type in AutoMapper
下一篇: automapper automapping deep object to flat object and back