job when a delayed task fails so it will auto
Our app is hosted on heroku and we use delayed job when sending info to a remote system (via a GET to a url with some url params)
the remote system returns a success code usually, but it it;s real busy it returns a tryagain code.
suppose the our method is
def send_info
the_url = "http://mydomain.com/dosomething?arg=#{self.someval}"
the_result = open(the_url).read
successflag = get_success_flag_from(the_result)
end
and so somewhere in our code we do
@widget.delay.send_info
and that all works fine.
Except it does not automatically handle the case where the remote said to try back later.
Is there any way for the send_info method (which is what delayed job will execute) to "tell" delayed_job "retry me again"? Do we need to throw some custom exception or something?
Raising any kind of exception ought to cause delayed_job to requeue it (subject to only-trying-so-many-times); if you don't especially need a custom exception you can just raise a RuntimeError .
上一篇: 红宝石在轨道上