如何迭代SparseArray？
有没有办法来迭代Java SparseArray（Android版）？ 我用sparsearray很容易通过索引获取值。 我找不到一个。
似乎我找到了解决方案。 我没有正确注意到keyAt(index)函数。
所以我会像这样去做：
for(int i = 0; i < sparseArray.size(); i++) {
int key = sparseArray.keyAt(i);
// get the object by the key.
Object obj = sparseArray.get(key);
}
如果您不关心这些键，那么可以在遍历稀疏数组时直接使用valueAt(int)来直接访问这些值。
for(int i = 0, nsize = sparseArray.size(); i < nsize; i++) {
Object obj = sparseArray.valueAt(i);
}
你只需创建你自己的ListIterator：
public final class SparseArrayIterator<E> implements ListIterator<E> {
private final SparseArray<E> array;
private int cursor;
private boolean cursorNowhere;
/**
* @param array
* to iterate over.
* @return A ListIterator on the elements of the SparseArray. The elements
* are iterated in the same order as they occur in the SparseArray.
* {@link #nextIndex()} and {@link #previousIndex()} return a
* SparseArray key, not an index! To get the index, call
* {@link android.util.SparseArray#indexOfKey(int)}.
*/
public static <E> ListIterator<E> iterate(SparseArray<E> array) {
return iterateAt(array, -1);
}
/**
* @param array
* to iterate over.
* @param key
* to start the iteration at. {@link android.util.SparseArray#indexOfKey(int)}
* < 0 results in the same call as {@link #iterate(android.util.SparseArray)}.
* @return A ListIterator on the elements of the SparseArray. The elements
* are iterated in the same order as they occur in the SparseArray.
* {@link #nextIndex()} and {@link #previousIndex()} return a
* SparseArray key, not an index! To get the index, call
* {@link android.util.SparseArray#indexOfKey(int)}.
*/
public static <E> ListIterator<E> iterateAtKey(SparseArray<E> array, int key) {
return iterateAt(array, array.indexOfKey(key));
}
/**
* @param array
* to iterate over.
* @param location
* to start the iteration at. Value < 0 results in the same call
* as {@link #iterate(android.util.SparseArray)}. Value >
* {@link android.util.SparseArray#size()} set to that size.
* @return A ListIterator on the elements of the SparseArray. The elements
* are iterated in the same order as they occur in the SparseArray.
* {@link #nextIndex()} and {@link #previousIndex()} return a
* SparseArray key, not an index! To get the index, call
* {@link android.util.SparseArray#indexOfKey(int)}.
*/
public static <E> ListIterator<E> iterateAt(SparseArray<E> array, int location) {
return new SparseArrayIterator<E>(array, location);
}
private SparseArrayIterator(SparseArray<E> array, int location) {
this.array = array;
if (location < 0) {
cursor = -1;
cursorNowhere = true;
} else if (location < array.size()) {
cursor = location;
cursorNowhere = false;
} else {
cursor = array.size() - 1;
cursorNowhere = true;
}
}
@Override
public boolean hasNext() {
return cursor < array.size() - 1;
}
@Override
public boolean hasPrevious() {
return cursorNowhere && cursor >= 0 || cursor > 0;
}
@Override
public int nextIndex() {
if (hasNext()) {
return array.keyAt(cursor + 1);
} else {
throw new NoSuchElementException();
}
}
@Override
public int previousIndex() {
if (hasPrevious()) {
if (cursorNowhere) {
return array.keyAt(cursor);
} else {
return array.keyAt(cursor - 1);
}
} else {
throw new NoSuchElementException();
}
}
@Override
public E next() {
if (hasNext()) {
if (cursorNowhere) {
cursorNowhere = false;
}
cursor++;
return array.valueAt(cursor);
} else {
throw new NoSuchElementException();
}
}
@Override
public E previous() {
if (hasPrevious()) {
if (cursorNowhere) {
cursorNowhere = false;
} else {
cursor--;
}
return array.valueAt(cursor);
} else {
throw new NoSuchElementException();
}
}
@Override
public void add(E object) {
throw new UnsupportedOperationException();
}
@Override
public void remove() {
if (!cursorNowhere) {
array.remove(array.keyAt(cursor));
cursorNowhere = true;
cursor--;
} else {
throw new IllegalStateException();
}
}
@Override
public void set(E object) {
if (!cursorNowhere) {
array.setValueAt(cursor, object);
} else {
throw new IllegalStateException();
}
}
}