查询以检测重复的行

我已经通过使用c＃从一个XML文件读取数据到DataSet中，而不是我想要识别该集合中的重复（完全相同）的行。 我尝试了这样的分组，并且可行！

var d= from r1 in table.AsEnumerable()
       group r1 by new
       {
            t0 = r1[0],
            t1 = r1[1],
            t2 = r1[2],
            t3 = r1[3],
            t4 = r1[4],
            t5 = r1[5],
            t6 = r1[6],
            t7 = r1[7],
            t8 = r1[8],
       }
       into grp
       where grp.Count() > 1
       select grp;

但是数据列的数量可能不同，所以我不能在上面的查询中应用静态分组。 我不得不动态地生成分组数组？

我不想删除dublicate，我只是想找到它们！

---

var rows = table.AsEnumerable();
var unique = rows.Distinct(DataRowComparer.Default);
var duplicates = rows.Except(unique); // , DataRowComparer.Default);

---

尝试这个

DataTable dt = TableName;
dt = oPerformance.RemoveDuplicateRows(dt, ColToCompareAndRemove);

这里是RemoveDuplicateRows函数

public DataTable RemoveDuplicateRows(DataTable dTable, string colName)
        {
            Hashtable hTable = new Hashtable();
            ArrayList duplicateList = new ArrayList();

            //Add list of all the unique item value to hashtable, which stores combination of key, value pair.
            //And add duplicate item value in arraylist.
            foreach (DataRow drow in dTable.Rows)
            {
                if (hTable.Contains(drow[colName]))
                    duplicateList.Add(drow);
                else
                    hTable.Add(drow[colName], string.Empty);
            }

            //Removing a list of duplicate items from datatable.
            foreach (DataRow dRow in duplicateList)
                dTable.Rows.Remove(dRow);

            //Datatable which contains unique records will be return as output.
            return dTable;
        }

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