(Deep) copying an array using jQuery

2018-05-31 10:22:46

Possible Duplicate:
What is the most efficient way to clone a JavaScript object?

I need to copy an (ordered, not associative) array of objects. I'm using jQuery. I initially tried

jquery.extend({}, myArray)

but, naturally, this gives me back an object, where I need an array (really love jquery.extend, by the way).

So, what's the best way to copy an array?

Since Array.slice() does not do deep copying, it is not suitable for multidimensional arrays:

var a =[[1], [2], [3]];
var b = a.slice();

b.shift().shift();
// a is now [[], [2], [3]]

Note that although I've used shift().shift() above, the point is just that b[0][0] contains a pointer to a[0][0] rather than a value.

Likewise delete(b[0][0]) also causes a[0][0] to be deleted and b[0][0]=99 also changes the value of a[0][0] to 99.

jQuery's extend method does perform a deep copy when a true value is passed as the initial argument:

var a =[[1], [2], [3]];
var b = $.extend(true, [], a);

b.shift().shift();
// a is still [[1], [2], [3]]

$.extend(true, [], [['a', ['c']], 'b'])

这应该为你做。

I realize you're looking for a "deep" copy of an array, but if you just have a single level array you can use this:

Copying a native JS Array is easy. Use the Array.slice() method which creates a copy of part/all of the array.

var foo = ['a','b','c','d','e'];
var bar = foo.slice();

now foo and bar are 5 member arrays of 'a','b','c','d','e'

of course bar is a copy, not a reference... so if you did this next...

bar.push('f');
alert('foo:' + foo.join(', '));
alert('bar:' + bar.join(', '));

you would now get:

foo:a, b, c, d, e
bar:a, b, c, d, e, f

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