PHP
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mysql_fetch_array（）期望参数1是资源，布尔在select中给出
警告：mysql_fetch_ *期望参数1是资源，布尔给定错误
我试图从表中选择数据，但得到这个错误信息！
mysql_fetch_array（）期望参数1是资源，布尔在select中给出
我实际上在php中使用分页...但它对于更简单的查询很好，只有WHERE中只有一个条件...但是这里...有多个条件，它不起作用完整的代码是：
<?php
/*
Place code to connect to your DB here.
*/
$con=mysql_connect("localhost","root","password");
if(!$con)
{
die('could not connect:'.mysql_error());
}
mysql_select_db("database",$con);
//$page=1; // initialise page
$tbl_name="posts"; //your table name
// How many adjacent pages should be shown on each side?
$adjacents = 3;
$query = $_GET['query'];
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
/*
First get total number of rows in data table.
If you have a WHERE clause in your query, make sure you mirror it here.
*/
$query = "SELECT COUNT(*) as num FROM posts WHERE status='active' AND ((title LIKE '%".$query."%') OR (content LIKE '%".$query."%'))";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages['num'];
/* Setup vars for query. */
$targetpage = "index.php"; //your file name (the name of this file)
$limit = 20; //how many items to show per page
/*if($_GET['page']="")
{
$page=2;
}
else
{
$page = $_GET['page'];
}*/
if(empty($_GET['page']))
{
$page=1;
}
else
{
$page = $_GET['page'];
}
if($page)
$start = ($page - 1) * $limit; //first item to display on this page
else
$start = 0; //if no page var is given, set start to 0
/* Get data. */
$sql = "SELECT*FROM $tbl_name WHERE status='active' AND ((title LIKE '%".$query."%') OR (content LIKE '%".$query."%')) ORDER BY postid DESC LIMIT $start, $limit";
$result = mysql_query($sql);
/* Setup page vars for display. */
if ($page == 0) $page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit); //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class="pagination">";
//previous button
if ($page > 1)
$pagination.= "<a href="$targetpage?page=$prev">previous</a>";
else
$pagination.= "<span class="disabled">previous</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class="current">$counter</span>";
else
$pagination.= "<a href="$targetpage?page=$counter">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class="current">$counter</span>";
else
$pagination.= "<a href="$targetpage?page=$counter">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href="$targetpage?page=$lpm1">$lpm1</a>";
$pagination.= "<a href="$targetpage?page=$lastpage">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href="$targetpage?page=1">1</a>";
$pagination.= "<a href="$targetpage?page=2">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class="current">$counter</span>";
else
$pagination.= "<a href="$targetpage?page=$counter">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href="$targetpage?page=$lpm1">$lpm1</a>";
$pagination.= "<a href="$targetpage?page=$lastpage">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href="$targetpage?page=1">1</a>";
$pagination.= "<a href="$targetpage?page=2">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class="current">$counter</span>";
else
$pagination.= "<a href="$targetpage?page=$counter">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href="$targetpage?page=$next">next</a>";
else
$pagination.= "<span class="disabled">next</span>";
$pagination.= "</div>n";
}
?>
<?php
while($row = mysql_fetch_array($result))
{
echo '<br><h3><a href="post.php?postid='.$row['postid'].'">'.$row['title'].'</a></h3>';
echo "<font size=4><br>".substr($row['content'], 0,300)."... </font>";
echo '<a href="post.php?postid='.$row['postid'].'">More details</a><br>';
}
?>
<?=$pagination?>
有什么问题？
mysql_query失败时返回FALSE
不知道错误在哪里，但你可以尝试做的事情是这样的：
$sQuery_select_stuff = " SELECT * FROM stuff WHERE stuff_id = 1";
$rResultaat_select_stuff = mysql_query($sQuery_select_stuff) or die(mysql_error());
$total_pages = mysql_fetch_array($rResultaat_select_stuff);
回声你的$查询变量，看看它是否你期望它
$query = $_GET['query'];
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
echo $query;
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