not show a parse error?

2018-06-24 18:51:12

I was running the following PHP code:

<?php 
    </script>
?>

There were no parse errors and the output was " ?> " (example).

In similar cases I do get a parse error:

<?php 
    </div>
?>

Parse error: syntax error, unexpected '<' in ...

Why doesn't <?php </script> ?> give the same error?

This must be because there are various ways of starting a block of PHP code:

<? ... ?> <? ... ?> (known as short_open_tag )

<?php ... ?> (the standard really)

<script language="php"> ... </script> (not recommended)

<% ... %> (deprecated and removed ASP-style tag after 5.3.0)

Apparently, you can open a PHP block one way, and close it the other. Didn't know that.

So in your code, you opened the block using <? but PHP recognizes </script> as the closer. What happened was:

<?php       <----- START PHP
</script>   <----- END PHP
?>          <----- JUST GARBAGE IN THE HTML

In PHP, you can use the script tag to open a PHP block.

So you can use

<script language="php">
    echo 'hello world';
</script>

So in your example you have mixed the normal open tag, <?php , with the closing tag, </script> . So the parser assumes that all the text after the closing script tag is normal HTML .