解析错误：语法错误，意外的T
解析错误：语法错误，第25行的StatusIG.php中出现意外的'if'（T_IF）
我真的没有看到我的代码有任何问题，为什么发生这种情况，请帮助。 我是一名PHP初学者
我的LINE 25是>> if（$ status == 0）
$accountdb_ip = "ip"; //Accountserver-IP
$accountdb_login = "acc"; //Accountserver-Loginname
$accountdb_pw = "psw"; //Accountserver-Passwort
$db_ip = "ip"; //DB-Server-IP
$db_login = "acc"; //DB-Server-Loginname
$db_pw = "psw"; //DB-Server-Passwort
$con = mysql_connect($db_ip, $db_login, $db_pw);
$con_account = mysql_connect($accountdb_ip, $accountdb_login, $accountdb_pw);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
$name = mysql_real_escape_string($_GET["name"], $con);
$result_id = mysql_query("SELECT * FROM player.player WHERE name='".$name."' LIMIT 1", $con);
$player_acc_id = mysql_result($result_id, 0, "account_id");
$result = mysql_query("SELECT * FROM account.account WHERE id='".$player_acc_id."'", $con);
$status = mysql_result($result, 0, "raiguard")
if($status == 0)
{echo "0";}
elseif($status == 1)
{echo "1";}
elseif($status == 2)
{echo "2";}
mysql_close($con);
mysql_close($con_account);
您错过了以下分号：
$status = mysql_result($result, 0, "raiguard")
将其替换为：
$status = mysql_result($result, 0, "raiguard");