PHP Parse error: syntax error

 

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  • PHP parse/syntax errors; and how to solve them? 13 answers

    • Change WHERE 'age' !="" to WHERE 'age' !=''

    Use 

    $query = mysqli_query($con, "SELECT a.* FROM (SELECT `id` as `id`, `age` as `age` FROM `register` WHERE `age` !='') as a INNER JOIN (SELECT `one` as `f1` FROM `friends` WHERE `two`='".$my_id."' UNION SELECT `two` as `f2` FROM `friends` WHERE `one` = '".$my_id."') as b ON a.id=b.f1");

    你应该在这里避免双引号

    WHERE `age` != ""
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