信用卡验证器的Java
我需要做一个信用卡号码验证。
当我谷歌搜索时，我发现了org.apache.commons.validator.CreditCardValidator 。 但似乎它不能正常工作。 当我传递一个非数字字符时，它也是真实的。
Apache CreditCardValidator的代码：
String ccNumber = "378282246310005";
CreditCardValidator creditCardValidator = new CreditCardValidator();
if(!creditCardValidator.isValid(ccNumber)) throw new Exception("Credit Card Number is not a valid one!");
然后，我根据卡的类型和卡号（使用luhn算法）编写了以下方法来验证信用卡号码。
CardType验证器（如果卡类型无效，则为null）
public String getCCType(String ccNumber){
String visaRegex = "^4[0-9]{12}(?:[0-9]{3})?$";
String masterRegex = "^5[1-5][0-9]{14}$";
String amexRegex = "^3[47][0-9]{13}$";
String dinersClubrRegex = "^3(?:0[0-5]|[68][0-9])[0-9]{11}$";
String discoverRegex = "^6(?:011|5[0-9]{2})[0-9]{12}$";
String jcbRegex = "^(?:2131|1800|35d{3})d{11}$";
String commonRegex = "^(?:4[0-9]{12}(?:[0-9]{3})?|5[1-5][0-9]{14}|6(?:011|5[0-9][0-9])[0-9]{12}|3[47][0-9]{13}|3(?:0[0-5]|[68][0-9])[0-9]{11}|(?:2131|1800|35d{3})d{11})$";
try {
ccNumber = ccNumber.replaceAll("D", "");
return (ccNumber.matches(visaRegex) ? "VISA" : ccNumber.matches(masterRegex) ? "MASTER" :ccNumber.matches(amexRegex) ? "AMEX" :ccNumber.matches(dinersClubrRegex) ? "DINER" :ccNumber.matches(discoverRegex) ? "DISCOVER" :ccNumber.matches(jcbRegex) ? "JCB":null);
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
CardNumber验证器使用Luhn的算法。
public boolean isValidCardNumber(String ccNumber){
try {
ccNumber = ccNumber.replaceAll("D", "");
char[] ccNumberArry = ccNumber.toCharArray();
int checkSum = 0;
for(int i = ccNumberArry.length - 1; i >= 0; i--){
char ccDigit = ccNumberArry[i];
if((ccNumberArry.length - i) % 2 == 0){
int doubleddDigit = Character.getNumericValue(ccDigit) * 2;
checkSum += (doubleddDigit % 9 == 0 && doubleddDigit != 0) ? 9 : doubleddDigit % 9;
}else{
checkSum += Character.getNumericValue(ccDigit);
}
}
return (checkSum != 0 && checkSum % 10 == 0);
} catch (Exception e) {
e.printStackTrace();
}
return false;
}
我想知道，
参考文献：如何根据数字检测信用卡类型？
您可以在这里找到信用卡验证器的自定义植入，它同时进行信用卡号码验证和信用卡类型检测，
http://www.esupu.com/credit-card-validator-java/
我很久以前做过这件事，对不起，代码是在C.轻松转换。 希望这会帮助你。
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
int CardNoChecker(unsigned long long int Number)
{
int dijts=0;
int Ans=0;
{
unsigned long long int k=1;
while(Number%k!=Number)
{
dijts=dijts+1;
k=k*10;
}
}
{
int i=1;
int Product=0;
int Sum=0;
for(i=dijts;i>=1;i--)
{
if(i%2==0)
{
if((Number%10)*2<10)
Product = Product + ( Number % 10 ) * 2 ;
else
{
int No=(Number%10)*2;
Product = Product + No/10;
Product = Product + No%10;
}
}
else
{
Sum = Sum + ( Number % 10 ) ;
}
Number=Number /10;
}
Ans = Sum + Product ;
}
if(Ans%10==0)
return (1);
else
return (0);
}
int main()
{
unsigned long long int CardNO;
int valid=0;
while(!valid)
{
int CnV=0;
int VC=0;
int AE=0;
int MC=0;
printf("Enter Card NO : ");
scanf("%llu",&CardNO);
if(CardNO/1000000000000==4 || CardNO/1000000000000000==4)
{
VC=1;
}
else if(CardNO/10000000000000==34 ||CardNO/10000000000000==37)
{
AE=1;
}
else if(CardNO/100000000000000==51 || CardNO/100000000000000==52 || CardNO/100000000000000==53 || CardNO/100000000000000==54 || CardNO/100000000000000==55)
{
MC=1;
}
CnV=CardNoChecker(CardNO);
if(CnV && MC )
printf("This is a Valid Master Cardnn");
else if(CnV && VC )
printf("This is a Valid Visa Cardnn");
else if(CnV && AE )
printf("This is a Valid American Express Cardnn");
else
printf("Card is Not Valid'nn");
}
return (0);
}